Chapter 13: Problem 8
$$ \mathbf{F}(x, y)=(2 y-3 x) \mathbf{i}+(2 y+3 x) \mathbf{j} $$
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Chapter 13: Problem 8
$$ \mathbf{F}(x, y)=(2 y-3 x) \mathbf{i}+(2 y+3 x) \mathbf{j} $$
These are the key concepts you need to understand to accurately answer the question.
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Find \(\operatorname{div}(\operatorname{curl} \mathbf{F})=\nabla \cdot(\nabla \times \mathbf{F})\) $$ \mathbf{F}(x, y, z)=x^{2} z \mathbf{i}-2 x z \mathbf{j}+y z \mathbf{k} $$
In Exercises 41 and \(42,\) evaluate \(\int_{C} \mathbf{F} \cdot d \mathbf{r}\) for each curve. Discuss the orientation of the curve and its effect on the value of the integral. \(\mathbf{F}(x, y)=x^{2} \mathbf{i}+x y \mathbf{j}\) (a) \(\mathbf{r}_{1}(t)=2 t \mathbf{i}+(t-1) \mathbf{j}, \quad 1 \leq t \leq 3\) (b) \(\mathbf{r}_{2}(t)=2(3-t) \mathbf{i}+(2-t) \mathbf{j}, \quad 0 \leq t \leq 2\)
Demonstrate the property that \(\int_{C} \mathbf{F} \cdot d \mathbf{r}=\mathbf{0}\) regardless of the initial and terminal points of \(C,\) if the tangent vector \(\mathbf{r}^{\prime}(t)\) is orthogonal to the force field \(\mathbf{F}\) \(\mathbf{F}(x, y)=x \mathbf{i}+y \mathbf{j}\) \(C: \mathbf{r}(t)=3 \sin t \mathbf{i}+3 \cos t \mathbf{j}\)
Evaluate the integral \(\int_{C}(2 x-y) d x+(x+3 y) d y\) along the path \(C\). \(C:\) arc on \(y=1-x^{2}\) from (0,1) to (1,0)
Consider a wire of density \(\rho(x, y)\) given by the space curve \(C: \mathbf{r}(t)=x(t) \mathbf{i}+y(t) \mathbf{j}, \quad a \leq t \leq b\) The moments of inertia about the \(x\) - and \(y\) -axes are given by \(I_{x}=\int_{C} y^{2} \rho(x, y) d s\) and \(I_{y}=\int_{C} x^{2} \rho(x, y) d s\) Find the moments of inertia for the wire of density \(\boldsymbol{\rho}\). A wire lies along \(\mathbf{r}(t)=a \cos t \mathbf{i}+a \sin t \mathbf{j}, 0 \leq t \leq 2 \pi\) and \(a>0,\) with density \(\rho(x, y)=y\)
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