Chapter 11: Problem 16
Find both first partial derivatives. \(z=\ln \left(x^{2}-y^{2}\right)\)
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Chapter 11: Problem 16
Find both first partial derivatives. \(z=\ln \left(x^{2}-y^{2}\right)\)
These are the key concepts you need to understand to accurately answer the question.
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Find \(d w / d t\) (a) using the appropriate Chain Rule and (b) by converting \(w\) to a function of \(t\) before differentiating. \(w=x y+x z+y z, \quad x=t-1, \quad y=t^{2}-1, \quad z=t\)
The parametric equations for the paths of two projectiles are given. At what rate is the distance between the two objects changing at the given value of \(t ?\) \(x_{1}=48 \sqrt{2} t, y_{1}=48 \sqrt{2} t-16 t^{2}\) \(x_{2}=48 \sqrt{3} t, y_{2}=48 t-16 t^{2}\) \(t=1\)
Consider the function \(w=f(x, y),\) where \(x=r \cos \theta\) and \(y=r \sin \theta .\) Prove each of the following. (a) \(\frac{\partial w}{\partial x}=\frac{\partial w}{\partial r} \cos \theta-\frac{\partial w}{\partial \theta} \frac{\sin \theta}{r}\) \(\frac{\partial w}{\partial y}=\frac{\partial w}{\partial r} \sin \theta+\frac{\partial w}{\partial \theta} \frac{\cos \theta}{r}\) (b) \(\left(\frac{\partial w}{\partial x}\right)^{2}+\left(\frac{\partial w}{\partial y}\right)^{2}=\left(\frac{\partial w}{\partial r}\right)^{2}+\left(\frac{1}{r^{2}}\right)\left(\frac{\partial w}{\partial \theta}\right)^{2}\)
Find the gradient of the function and the maximum value of the directional derivative at the given point. $$ \frac{\text { Function }}{h(x, y)=y \cos (x-y)} \frac{\text { Point }}{\left(0, \frac{\pi}{3}\right)} $$
Differentiate implicitly to find the first partial derivatives of \(z\) \(x+\sin (y+z)=0\)
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