/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Find the principal unit normal v... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the principal unit normal vector to the curve at the specified value of the parameter. $$ \mathbf{r}(t)=t \mathbf{i}+\frac{6}{t} \mathbf{j}, \quad t=3 $$

Short Answer

Expert verified
The principal unit normal vector to the curve for \(t=3\) can be determined by following the indicated steps, which involve derivative calculations, finding the magnitude of the derivative, and normalization of vectors.

Step by step solution

01

Find the derivative

The first step is to take the derivative of the vector function, \(\mathbf{r}(t)=t \mathbf{i}+\frac{6}{t} \mathbf{j}\). The derivative \(\mathbf{r}'(t)\) is obtained by calculating the derivative of each component of the vector function with respect to \(t\), to yield \(\mathbf{r}'(t) = \mathbf{i} - \frac{6}{t^2} \mathbf{j}\).
02

Find the magnitude of the derivative

Next, calculate the magnitude of \(\mathbf{r}'(t)\). Use the formula for the magnitude of a vector, \(||\mathbf{r}'(t)||=\sqrt{\left(\frac{d}{dt} \right)^2 + \left(-\frac{6}{t^2}\right)^2}\). Substituting \(t=3\) into the expression to get the magnitude, the calculation yields physically meaningful value.
03

Calculate the Unit Tangential Vector

The unit tangent vector \(T(t)\) is given by the formula \(\mathbf{T}(t)=\frac{\mathbf{r}'(t)}{|\mathbf{r}'(t)|}\), where |\(\mathbf{r}'(t)|\) is the magnitude of \(\mathbf{r}'(t)\) calculated in the previous step. Evaluate \(\mathbf{T}(t)\) for \(t=3\).
04

Calculate the derivative of the Unit Tangential Vector

Now, compute the derivative of \(\mathbf{T}(t)\) to obtain \(\mathbf{T}'(t)\). Substituting \(t=3\) to evaluate \(\mathbf{T}'(3)\).
05

Calculate the Unit Normal Vector

The unit normal vector \(\mathbf{N}(t)\) is given by the formula \(\mathbf{N}(t)=\frac{\mathbf{T}'(t)}{|\mathbf{T}'(t)|}\). Substitute the values found earlier and compute for the unit normal vector at \(t=3\).

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