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Find the limits. \(f(x)=4-x^{2}, g(x)=\sqrt{x+1}\) (a) \(\lim _{x \rightarrow 1} f(x)\) (b) \(\lim _{x \rightarrow 3} g(x)\) (c) \(\lim _{x \rightarrow 1} g(f(x))\)

Short Answer

Expert verified
\(\lim _{x \rightarrow 1} f(x) = 3, \lim _{x \rightarrow 3} g(x) = 2, \lim _{x \rightarrow 1} g(f(x)) = 2\)

Step by step solution

01

Evaluate \(\lim _{x \rightarrow 1} f(x)\)

Substitute \(x = 1\) into \(f(x)\) to find \(\lim _{x \rightarrow 1} f(x)\). As a result, \(f(1) = 4 - 1^{2} = 3\). Therefore, \(\lim _{x \rightarrow 1} f(x) = 3\)
02

Evaluate \(\lim _{x \rightarrow 3} g(x)\)

Substitute \(x = 3\) into \(g(x)\) to find \(\lim _{x \rightarrow 3} g(x)\). Accordingly, \(g(3) = \sqrt{3 + 1} = \sqrt{4} = 2\). Thus, \(\lim _{x \rightarrow 3} g(x) = 2\)
03

Evaluate \(\lim _{x \rightarrow 1} g(f(x))\)

Substitute \(x = 1\) into \(f(x)\) first, then substitute this output into \(g(x)\) to find \(\lim _{x \rightarrow 1} g(f(x))\). Specifically, \(f(1) = 3\) (from step 1) and substituting this into \(g(x)\), \(g(3) = 2\) (from step 2). Therefore, \(\lim _{x \rightarrow 1} g(f(x)) = 2\)

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