Chapter 7: Problem 2
Expand \(\frac{1}{1-Z}\) where \(-1
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Chapter 7: Problem 2
Expand \(\frac{1}{1-Z}\) where \(-1
These are the key concepts you need to understand to accurately answer the question.
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The velocity flow, \(\bar{v}\), of a liquid along a channel satisfies $$ v^{3}-6 v^{2}-348 v+3112=0 $$ Given that there is a root of this equation between \(v=10\) and \(v=11\), find this root correct to 3 d.p.
Obtain the equations of the tangent and normal of the following curves at the corresponding point: a \(y=x^{2}-3, \quad x=2\) b \(y=\cos (x), \quad x=\frac{\pi}{2}\) c \(y=e^{x}, \quad x=1\) d \(y=\ln (x), \quad x=1\)
The displacement, s, of a particle is given by $$ s=t^{3}-6 t^{2}+12 t $$
Show that for any given volume, \(V\), the minimum surface area required for a closed cylindrical can is when the height, \(h\), is twice the radius, \(r\).
A projectile is fired vertically upwards with height \(h\) given by $$ \begin{aligned} h &=25 t-4.9 t^{2} \\ & \text { where } \quad 0 \leq t \leq 5 \end{aligned} $$ Find expressions for the velocity and acceleration. Determine the maximum height reached by the projectile.
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