Chapter 4: Problem 4
What is the time displacement between the following waves? a \(A \sin \left(5 t+\frac{\pi}{5}\right)\) and \(A \sin \left(5 t-\frac{\pi}{7}\right)\) b \(\cos (7 t-0.26)\) and \(5 \cos (7 t+\pi)\) c \(\cos \left(2 t+\frac{\pi}{2}\right)\) and \(\cos \left(2 t+\frac{\pi}{3}\right)\)
Short Answer
Expert verified
(a) \(\frac{12}{175}\pi\), (b) \(-0.486\), (c) \(\frac{\pi}{12}\)
Step by step solution
01
Understand the General Form
In order to find the time displacement between two waves, use the general form: \(\text{{wave}} = A \sin (\omega t + \phi)\) or\(\text{{wave}} = A \cos (\omega t + \phi)\).The phase difference between the waves can be found by comparing the phase angles \(\phi\). The time displacement \(\Delta t\) can then be found using:\[ \Delta t = \frac{\Delta \phi}{\omega} \]
02
Find Phase Difference for Part (a)
Compare the phase angles of the given sine waves: \(A \sin (5 t+\frac{\pi}{5})\) and \(A \sin (5 t-\frac{\pi}{7})\).The phase difference \(\Delta \phi\) between the two waves is:\[ \Delta \phi = \left( \frac{\pi}{5} \right) - \left( -\frac{\pi}{7} \right) \]Simplify the calculation:\[ \Delta \phi = \frac{\pi}{5} + \frac{\pi}{7} = \frac{7\pi}{35} + \frac{5\pi}{35} = \frac{12\pi}{35} \]
03
Calculate Time Displacement for Part (a)
The angular frequency \(\omega = 5\) and phase difference \(\Delta \phi = \frac{12\pi}{35}\).Using the formula:\[ \Delta t = \frac{\Delta \phi}{\omega} = \frac{\frac{12\pi}{35}}{5} = \frac{12\pi}{175} = \frac{12}{175}\pi \]The time displacement \(\Delta t\) for part (a) is \(\frac{12}{175}\pi\).
04
Find Phase Difference for Part (b)
Compare the phase angles of the given cosine waves:\(\cos (7 t-0.26)\) and \(5\cos (7 t+\pi)\).The phase difference \(\Delta \phi\) between the two waves is:\[ \Delta \phi = \left( -0.26 \right) - \left( +\pi \right) = -0.26 - \pi \]Simplify the calculation:\[ \Delta \phi = -0.26 - 3.1416 = -3.4016 \]
05
Calculate Time Displacement for Part (b)
The angular frequency \(\omega = 7\) and phase difference \(\Delta \phi = -3.4016\).Using the formula:\[ \Delta t = \frac{\Delta \phi}{\omega} = \frac{-3.4016}{7} = -0.486 \]The time displacement \(\Delta t\) for part (b) is \(-0.486\).
06
Find Phase Difference for Part (c)
Compare the phase angles of the given cosine waves:\(\cos \left(2 t+\frac{\pi}{2}\right)\) and \(\cos \left(2 t+\frac{\pi}{3}\right)\).The phase difference \(\Delta \phi\) between the two waves is:\[ \Delta \phi = \left( \frac{\pi}{2} \right) - \left( \frac{\pi}{3} \right) \]Simplify the calculation:\[ \Delta \phi = \frac{3\pi}{6} - \frac{2\pi}{6} = \frac{\pi}{6} \]
07
Calculate Time Displacement for Part (c)
The angular frequency \(\omega = 2\) and phase difference \(\Delta \phi = \frac{\pi}{6}\).Using the formula:\[ \Delta t = \frac{\Delta \phi}{\omega} = \frac{\frac{\pi}{6}}{2} = \frac{\pi}{12} \]The time displacement \(\Delta t\) for part (c) is \(\frac{\pi}{12}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phase Difference
Phase difference is a crucial concept when studying waves. It refers to the difference in the phase angles of two waves measured at a specific point in time. Think of it as the shift between the waves. In mathematical terms:
- Phase difference, \Delta \phi, is determined by: \[ \Delta \phi = \phi_1 - \phi_2 \]
Angular Frequency
Angular frequency, denoted by \omega, indicates how quickly a wave oscillates in a given period. It is measured in radians per second (rad/s). The formula to calculate angular frequency is: \[ \omega = 2 \pi f \]
- Where \[f\text{ is the frequency of the wave in Hertz (Hz).}\text{Angular frequency bridges time and phase information for periodic functions.}\text{For instance, in part (b) of the problem, the angular frequency of the cosine waves is 7 rad/s, which plays a role in calculating time displacement.}\text{It tells us how fast the waves are oscillating, providing a direct link to determining time displacement from phase difference.} \]
Sine and Cosine Waves
Sine and cosine waves are fundamental in wave theory and often appear in trigonometry and physics. Both waves describe periodic oscillations but have a phase shift of \frac{ \pi } { 2 } radians. This means that sine and cosine waves are essentially the same, but one leads or lags the other by \frac{ \pi } { 2 } radians.
- These waves follow the equations: \[ __\text{Sine wave: y = A \sin ( \omega t + \phi )}__, __\text{Cosine wave: y = A \cos ( \omega t + \phi )}__ \]