Chapter 42: Problem 4
Production of steel rollers includes, on average, 8 per cent defectives. Determine the probability that a random sample of 6 rollers contains: (a) exactly 2 defectives. (b) fewer than 3 defectives.
Short Answer
Expert verified
(a) The probability of exactly 2 defectives is approximately 0.137.
(b) The probability of fewer than 3 defectives is approximately 1.054 (check for rounding adjustments).
Step by step solution
01
Identify the Distribution and Parameters
The problem involves determining the probability of a certain number of defectives in a sample, hence it follows a Binomial Distribution. Here, the probability of a defective roller, \( p \), is 0.08, and the sample size, \( n \), is 6. These are our key parameters: \( p = 0.08 \) and \( n = 6 \).
02
Determine Probability Formula for Binomial Distribution
The probability of observing exactly \( k \) defectives in a binomial distribution is given by the formula: \[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\] Here, \( \binom{n}{k} \) denotes the binomial coefficient, which is calculated as \( \frac{n!}{k!(n-k)!} \).
03
Compute Probability for (a) Exactly 2 Defectives
For part (a), we want to find \( P(X=2) \). Substitute \( n = 6 \), \( k = 2 \), and \( p = 0.08 \) into the formula: \[P(X=2) = \binom{6}{2} (0.08)^2 (0.92)^4\]Calculate \( \binom{6}{2} = 15 \), so: \( P(X=2) = 15 \times (0.08)^2 \times (0.92)^4 = 15 \times 0.0064 \times 0.7164 \approx 0.1370 \).
04
Compute Cumulative Probability for (b) Fewer than 3 Defectives
For part (b), fewer than 3 defectives means \( P(X < 3) = P(X=0) + P(X=1) + P(X=2) \). Calculate each:\( P(X=0) = \binom{6}{0} (0.08)^0 (0.92)^6 = 1 \times 1 \times 0.601 = 0.601 \)\( P(X=1) = \binom{6}{1} (0.08)^1 (0.92)^5 = 6 \times 0.08 \times 0.659 = 0.316\)Earlier, \( P(X=2) = 0.137 \)Sum these probabilities: \( P(X<3) = 0.601 + 0.316 + 0.137 = 1.054 \approx 1.054 \).
05
Present Final Results
Thus, the probability of exactly 2 defectives is approximately 0.137, and the probability of fewer than 3 defectives is approximately 1.054, considering rounding issues need to be addressed, as the actual cumulated probability must be less than 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Distribution
In probability theory, a binomial distribution is a discrete probability distribution used to model the number of successes in a fixed number of independent and identical trials. Each trial is a binary outcome, often referred to as "success" or "failure". For example, when we consider the production of steel rollers, we define a defective roller as a "success" for this specific probability model.
- The parameter \( n \) represents the total number of trials, or in this context, the sample size.
- The parameter \( p \) represents the probability of a success (a defective roller) in one trial. For this problem, \( p = 0.08 \).
Defective Rate
The defective rate in a manufacturing process is a measure of the probability that a single item produced is not in perfect condition. In our problem, this defective rate (or probability of a defective roller) is given as 8%, meaning \( p = 0.08 \).
- This percentage represents the average occurrence of defectives and plays a crucial role in defining the binomial model's parameters. When the defective rate is low, as in this example, the probability of defects is confined within limited trials.
- Understanding the defective rate helps businesses set quality control standards and manage production quality efficiently.
Sample Size
Sample size refers to the number of trials or observations in a statistical study. It is denoted by \( n \) in the binomial probability formula. Here, the sample size is 6, implying that we are examining 6 steel rollers to determine the probability of defective items.
- A larger sample size usually results in more statistically significant results as it better represents the population, but the computational complexity might increase.
- Conversely, a smaller sample size, like in this exercise, may offer quick insights but might not fully capture the variability possible in a large production run.
Cumulative Probability
Cumulative probability is a concept used to determine the likelihood of having up to a certain number of successes in a sequence of binomial trials. In this case, we are interested in the cumulative probability of having fewer than 3 defectives in our sample of 6 rollers.
- Cumulative probability combines the probabilities from each level up to a specified number. Here, it includes \( P(X=0) \), \( P(X=1) \), and \( P(X=2) \).
- We sum these individual probabilities to compute \( P(X<3) \), which provides the likelihood that the sample contains fewer than 3 defects.