Chapter 4: Problem 1
Given \(x^{2}-y^{2}=0\) find the equation giving \(y\) in terms of \(x\) and plot the graph of this equation for \(-3 \leq x \leq 3\)
Short Answer
Expert verified
The equation gives two graphs: lines $y = x$ and $y = -x$ for $-3 \leq x \leq 3$. Graph both to represent the solution.
Step by step solution
01
Recognize the Equation's Form
The given equation is $x^2 - y^2 = 0$. This is a difference of squares, which can be factored into $(x-y)(x+y) = 0$.
02
Solve for y in Terms of x
Set each factor from the factored equation equal to zero: \ 1. \(x-y = 0\) leads to \(y = x\) \ 2. \(x+y = 0\) leads to \(y = -x\). \ Thus, \(y\) can be expressed as either \(y = x\) or \(y = -x\) based on these two solutions.
03
Identify Graph Equations
The solutions $y = x$ and $y = -x$ represent two equations. These equations correspond to lines passing through the origin with slopes of $1$ and $-1$, respectively.
04
Plot the Graph
Create a graph with \(x\) on the horizontal axis and \(y\) on the vertical axis. Plot the two lines: for \(y = x\), draw a line through points like (\(-3\), \(-3\)), (0, 0), and (3, 3); for \(y = -x\), draw a line through points like (\(-3\), 3), (0, 0), and (3, -3). Both lines should be extended across the range \(-3 \leq x \leq 3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorization
Factorization is a process used to simplify mathematical expressions and solve equations. It involves breaking down an expression into a product of simpler factors. This is particularly useful when dealing with polynomial equations. In the exercise given, we have the equation \(x^2 - y^2 = 0\). This is a classic example of the difference of squares, where you have two terms squared and subtracted from each other.
The difference of squares follows a special factorization pattern: \(a^2 - b^2 = (a-b)(a+b)\). In our case, \(x^2 - y^2\) can be rewritten as \((x-y)(x+y) = 0\).
The difference of squares follows a special factorization pattern: \(a^2 - b^2 = (a-b)(a+b)\). In our case, \(x^2 - y^2\) can be rewritten as \((x-y)(x+y) = 0\).
- Recognize the pattern of difference of squares.
- Apply the factorization formula to split the expression into two linear factors.
- Set each factor equal to zero to find solutions.
Plotting Graphs
Plotting graphs is a visual method of representing mathematical equations. It helps in understanding the behavior, trends, and relationships in the equations. In our exercise, we have discovered two equations: \(y = x\) and \(y = -x\). These are linear equations and can be plotted on the Cartesian coordinate system.
To plot these graphs:
To plot these graphs:
- Understand the slope-intercept form of the equation \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
- For \(y = x\), the slope \(m\) is 1, indicating a diagonal line rising from left to right through the origin \((0,0)\).
- For \(y = -x\), the slope \(m\) is -1, producing a diagonal line falling from left to right through the origin.
- Identify key points on each line to aid in drawing: for \(y = x\), use points like \((-3,-3), (0,0), (3,3)\); for \(y = -x\), use \((-3,3), (0,0), (3,-3)\).
Difference of Squares
The difference of squares is a mathematical identity used to factor quadratic expressions that appear in the form \(a^2 - b^2\). This identity is fundamental in algebra and is expressed as \(a^2 - b^2 = (a-b)(a+b)\). It highlights a relationship between subtraction of squares and multiplication of sums and differences.
In our exercise, the expression \(x^2 - y^2\) is a perfect example of the difference of squares. Recognizing this form is critical in simplifying equations and involves these straightforward steps:
In our exercise, the expression \(x^2 - y^2\) is a perfect example of the difference of squares. Recognizing this form is critical in simplifying equations and involves these straightforward steps:
- Identify each term as a perfect square: \(x^2\) and \(y^2\).
- Apply the difference of squares formula to factor the expression: \((x-y)(x+y)\).
- Utilizing this identity transforms a simple-looking equation into two smaller and easier-to-solve equations: \(x-y = 0\) and \(x+y = 0\).