Chapter 38: Problem 14
\(\left(1+x^{2}\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+3 x y=5 x\), given that \(y=2\) when \(x=1\)
Short Answer
Expert verified
The solution is \(y = \frac{5x^2 + 5}{4} - \frac{\sqrt{2}}{(1+x^2)^{3/2}}\).
Step by step solution
01
Identify the Type of Differential Equation
The given differential equation is \((1+x^{2})\frac{\mathrm{d} y}{\mathrm{d} x} + 3xy = 5x\). This is a first-order linear differential equation of the form \(P(x)\frac{\mathrm{d} y}{\mathrm{d} x} + Q(x)y = R(x)\) with \(P(x) = 1+x^{2}\), \(Q(x) = 3x\), and \(R(x) = 5x\).
02
Find the Integrating Factor
To solve the differential equation, we must find the integrating factor \(\mu(x)\), where \(\mu(x) = e^{\int \frac{Q(x)}{P(x)} \mathrm{d}x}\). Evaluate \(\int \frac{3x}{1+x^{2}} \mathrm{d}x\). The integral can be solved using substitution \(u = 1+x^2\), giving \(\mu(x) = e^{\int \frac{3x}{1+x^2} \mathrm{d}x} = e^{\frac{3}{2}\ln(1+x^2)} = (1+x^2)^{3/2}\).
03
Solve the Differential Equation
Multiply the entire differential equation by the integrating factor \((1+x^2)^{3/2}\) to obtain \((1+x^2)^{3/2} \left((1+x^2)\frac{\mathrm{d}y}{\mathrm{d}x} + 3xy\right) = 5x(1+x^2)^{3/2}\). Recognize the left side as the derivative of \( ((1+x^2)^{3/2} y) \). Integrate both sides with respect to \(x\):\[ (1+x^2)^{3/2} y = \int 5x (1+x^2)^{3/2} \mathrm{d}x. \] This results in \((1+x^2)^{3/2} y = \left[\frac{(5x^2+5)(1+x^2)^{3/2}}{4}\right] + C\).
04
Apply Initial Condition
Use the initial condition \(y = 2\) when \(x = 1\) to find the constant \(C\). Substitute these values into the solution: \((1+1^2)^{3/2} \cdot 2 = \left[\frac{10(1+1^2)^{3/2}}{4}\right] + C\). Simplify to find \(4\sqrt{2} = 5\sqrt{2} + C\). Thus, \(C = -\sqrt{2}\).
05
Write the Final Solution
Substitute \(C\) back into the general solution: \[ (1+x^2)^{3/2} y = \left[\frac{(5x^2+5)(1+x^2)^{3/2}}{4}\right] - \sqrt{2}. \] Solve for \(y\) in terms of \(x\):\[ y = \frac{(5x^2+5)}{4} - \frac{\sqrt{2}}{(1+x^2)^{3/2}}. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integrating Factor
The integrating factor is a crucial tool when solving linear first-order differential equations. It allows us to transform a non-exact equation into one that is easily integrable. In our problem, the differential equation is
- \( (1+x^2) \frac{\mathrm{d} y}{\mathrm{d} x} + 3xy = 5x \).
- \( \mu(x) = e^{\int \frac{Q(x)}{P(x)} \mathrm{d}x} \).
- \( Q(x) = 3x \)
- \( P(x) = 1+x^2 \),
- \( (1+x^2)^{3/2} \).
Initial Condition
Initial conditions are necessary when solving differential equations, as they allow us to determine any arbitrary constants that appear during integration. In the context of first-order linear differential equations, like the one in our example, initial conditions ensure we find the unique solution applicable to a particular scenario. For this exercise, the initial condition provided is
- \( y = 2 \) when \( x = 1 \).
- \( C = -\sqrt{2} \).
Substitution Method
The substitution method is a powerful technique in calculus for dealing with integrals that are difficult to solve directly. In solving for the integrating factor of our given differential equation, substitution played a key role. We encountered the integral
- \( \int \frac{3x}{1+x^2} \mathrm{d}x \),
- \( u = 1 + x^2 \),
- \( \frac{\mathrm{d}u}{\mathrm{d}x} = 2x \),
- \((1+x^2)^{3/2} \).