Chapter 38: Problem 1
Solve the following differential equations: $$ x \frac{\mathrm{d} y}{\mathrm{~d} x}=x^{2}+2 x-3 $$
Short Answer
Expert verified
\(y = \frac{x^2}{2} + 2\ln|x| + \frac{3}{x} + C\)
Step by step solution
01
Identify the type of differential equation
The given equation is \(x \frac{\mathrm{d} y}{\mathrm{d} x} = x^2 + 2x - 3\). This is a first-order differential equation and can be recognized as a separable differential equation.
02
Separate variables
Rewriting the equation, we have \(\frac{\mathrm{d} y}{\mathrm{d} x} = x + \frac{2}{x} - \frac{3}{x^2}\). Separate the variables by dividing both sides by \(x\) and multiplying by \(\mathrm{d} x\): \(\mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x\).
03
Integrate both sides
Integrate both sides to find \(y\):\[y = \int \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x\]\[= \int x \mathrm{d} x + \int \frac{2}{x} \mathrm{d} x - \int \frac{3}{x^2} \mathrm{d} x\]
04
Solve each integral
Compute each integral separately:- \(\int x \mathrm{d} x = \frac{x^2}{2}\)- \(\int \frac{2}{x} \mathrm{d} x = 2\ln|x|\)- \(\int \frac{3}{x^2} \mathrm{d} x = -\frac{3}{x}\)Thus,\[y = \frac{x^2}{2} + 2\ln|x| - \left(-\frac{3}{x}\right) + C\]where \(C\) is the constant of integration.
05
Combine and simplify the solution
Combine the results from the previous step to write the general solution:\[y = \frac{x^2}{2} + 2\ln|x| + \frac{3}{x} + C\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Separable Differential Equations
Separable differential equations are a type of first-order differential equation that can be rewritten in a way that allows the variables to be separated on each side of the equation. This means that all terms involving the dependent variable (often denoted as \( y \)) are on one side and all terms involving the independent variable (often \( x \)) are on the other.
For instance, consider the equation \( x \frac{\mathrm{d} y}{\mathrm{d} x} = x^2 + 2x - 3 \). By rewriting and rearranging terms, we can express it as \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \). This separation of variables enables us to integrate each side with respect to its respective variable.
Key steps include:
For instance, consider the equation \( x \frac{\mathrm{d} y}{\mathrm{d} x} = x^2 + 2x - 3 \). By rewriting and rearranging terms, we can express it as \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \). This separation of variables enables us to integrate each side with respect to its respective variable.
Key steps include:
- Recognizing the equation as separable.
- Rearranging terms to isolate \( \mathrm{d} y \) on one side.
- Rewriting the equation to clearly separate \( y \) terms from \( x \) terms before integrating.
First-Order Differential Equations
First-order differential equations refer to equations involving the first derivative of an unknown function. They play a crucial role in modeling real-world phenomena such as population growth, thermodynamics, and electrical circuits.
These equations can generally be expressed in the form \( \frac{\mathrm{d} y}{\mathrm{d} x} = f(x, y) \), where \( f(x, y) \) is a given function of \( x \) and \( y \). In this exercise's context, the equation \( x \frac{\mathrm{d} y}{\mathrm{d} x} = x^2 + 2x - 3 \) fits this category because it involves the first derivative \( \frac{\mathrm{d} y}{\mathrm{d} x} \).
What separates these from higher-order differential equations is:
These equations can generally be expressed in the form \( \frac{\mathrm{d} y}{\mathrm{d} x} = f(x, y) \), where \( f(x, y) \) is a given function of \( x \) and \( y \). In this exercise's context, the equation \( x \frac{\mathrm{d} y}{\mathrm{d} x} = x^2 + 2x - 3 \) fits this category because it involves the first derivative \( \frac{\mathrm{d} y}{\mathrm{d} x} \).
What separates these from higher-order differential equations is:
- Simpler solutions as they involve a single integration step.
- Direct applicability in many physical and engineering problems.
- Often serve as a foundation for understanding more complex systems.
Integration Techniques
Solving differential equations often requires the use of integration, an essential calculus technique. This process involves finding a function whose derivative matches a specified function.
In our exercise, solving \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \) requires integrating each term separately:
In our exercise, solving \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \) requires integrating each term separately:
- \( \int x \mathrm{d} x = \frac{x^2}{2} \)
- \( \int \frac{2}{x} \mathrm{d} x = 2\ln|x| \)
- \( \int \frac{3}{x^2} \mathrm{d} x = -\frac{3}{x} \)
- Power Rule: Used to integrate terms like \( x^n \).
- Logarithmic Integration: Applied when integrating functions like \( \frac{1}{x} \).
- Handling Negative Exponents: Applicable for terms like \( x^{-2} \).
Constant of Integration
When solving differential equations through integration, you will often encounter the constant of integration, usually denoted as \( C \). This constant arises because indefinite integrals represent a family of functions that differ by a constant.
In the exercise's solution, after integrating the rearranged equation \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \), we include the constant \( C \) in the solution: \[ y = \frac{x^2}{2} + 2\ln|x| + \frac{3}{x} + C \]
Key points about the constant of integration include:
In the exercise's solution, after integrating the rearranged equation \( \mathrm{d} y = \left(x + \frac{2}{x} - \frac{3}{x^2}\right) \mathrm{d} x \), we include the constant \( C \) in the solution: \[ y = \frac{x^2}{2} + 2\ln|x| + \frac{3}{x} + C \]
Key points about the constant of integration include:
- It accounts for the arbitrary position where the integration can start on the graph.
- Different problems can require different specific values for \( C \), often determined by initial conditions or boundary values.
- Its inclusion is essential to represent the complete set of possible solutions to a differential equation.