Chapter 10: Problem 5
Given that \(f(x)=(5 x-4)^{3}-4\) decompose \(f\) into its component functions and find its inverse. Is the inverse a function?
Short Answer
Expert verified
The inverse function is \( f^{-1}(y) = \frac{(y + 4)^{1/3} + 4}{5} \). Yes, the inverse is a function.
Step by step solution
01
Understanding the Function
The given function is\[f(x) = (5x - 4)^3 - 4.\]The goal is to express this function in terms of simpler functions, since the original function can be decomposed into layers. It primarily consists of a linear component and powers with a constant.
02
Decompose into Component Functions
To decompose, recognize the following components:1. Linear function: \(g(x) = 5x - 4\)2. Cubic function: \(h(x) = x^3\)3. Constant subtraction: \(k(x) = x - 4\)Thus, the function can be expressed as a composition:\[f(x) = k(h(g(x))).\]
03
Express Function as Composition
Write the function as:- Start with \(g(x) = 5x - 4\)- Apply the cubic function: \(h(g(x)) = (5x - 4)^3\)- Subtract a constant: \(k(h(g(x))) = (5x - 4)^3 - 4\)Thus, \(f(x) = k(h(g(x)))\) is the complete expression.
04
Finding the Inverse Part 1 - Reverse the Components
To find the inverse, reverse the operations applied:Start with \(y = f(x) = (5x - 4)^3 - 4\). Solve for \(x\) by reversing each step.
05
Solve for x in Terms of y - Isolate the Cubic
Add 4 to both sides to isolate the cubic:\[y + 4 = (5x - 4)^3\]
06
Solve for x in Terms of y - Solve the Cubic
Take the cube root of both sides:\[(y + 4)^{1/3} = 5x - 4.\]
07
Solve for x in Terms of y - Isolate x
Solve for \(x\) by adding 4 and then dividing by 5:\[x = \frac{(y + 4)^{1/3} + 4}{5}.\]
08
Writing the Inverse Function
The inverse function \(f^{-1}(y)\) is expressed as:\[f^{-1}(y) = \frac{(y + 4)^{1/3} + 4}{5}.\]
09
Determine If the Inverse is a Function
For an inverse to be a function, it must pass the vertical line test. Since the original function \(f(x) = (5x - 4)^3 - 4\) is a one-to-one (monotonic) function, its inverse is also a function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Decomposition
When we talk about function decomposition, we refer to breaking a complex function into simpler, basic functions. This makes it easier to understand and analyze the function.
Given the function \(f(x) = (5x - 4)^3 - 4\), we decompose it into simpler component functions:
Given the function \(f(x) = (5x - 4)^3 - 4\), we decompose it into simpler component functions:
- First, notice the linear function component, \(g(x) = 5x - 4\). This is the starting point for using the input \(x\).
- Next, apply the cubic transformation, noted as \(h(x) = x^3\), to the linear transformation. This means you take \(g(x)\) and apply the cube to it.
- Finally, the function \(k(x) = x - 4\) represents the subtraction of a constant from the previously established cubic outcome.
Cubic Functions
Cubic functions are polynomial functions of degree three, characterized by the form \(ax^3 + bx^2 + cx + d\). In our example, the primary cubic component is found in the middle step, \(h(x) = x^3\).
Some important properties of cubic functions include:
Some important properties of cubic functions include:
- They can have up to three real roots, where the function crosses the x-axis.
- The graph of a cubic function usually has a characteristic S-shape.
- Cubic functions have one inflection point, where the curvature of the graph changes.
One-to-One Functions
A one-to-one function, or injective function, is a type of function where each input has a unique output. This characteristic is crucial when determining if a function has an inverse that is also a function.
For \(f(x) = (5x - 4)^3 - 4\), being one-to-one means that it passes the horizontal line test—no horizontal line intersects the graph of the function more than once. This property guarantees:
For \(f(x) = (5x - 4)^3 - 4\), being one-to-one means that it passes the horizontal line test—no horizontal line intersects the graph of the function more than once. This property guarantees:
- Every unique output correlates with one unique input.
- The function's inverse, \(f^{-1}(y)\), is also a function because it will pass the vertical line test.