Chapter 30: Problem 22
Determine the following: $$ \int \frac{\mathrm{d} x}{5+4 \cos ^{2} x} $$
Short Answer
Expert verified
The solution to the given integral is:
$$
-\frac{1}{2} \left(\frac{2}{\sqrt{5}} \tan ^{-1}\left(\frac{2 (\frac{1+\cos(2x)}{2}) + 6}{\sqrt{5}}\right) + C\right)
$$
Step by step solution
01
Substitute the identity
Replace the \(\cos^2x\) term with the identity:
$$
\int \frac{\mathrm{d} x}{5 + 4\left(\frac{1+\cos(2x)}{2}\right)}
$$
02
Simplify the expression
Combine the constant terms and simplify the expression inside the integral:
$$
\int \frac{\mathrm{d} x}{5 + 2(1+\cos(2x))}
$$
$$
\int \frac{\mathrm{d} x}{7 + 2\cos(2x)}
$$
03
Perform a substitution
Use the substitution \(u = 2x\), which implies that \(\dfrac{du}{2} = dx\). Rewrite the integral in terms of \(u\):
$$
\int \frac{\mathrm{d} u/(2)}{7 + 2\cos u}
$$
04
Factor out the constant
Factor the 1/2 outside the integral:
$$
\frac{1}{2} \int \frac{\mathrm{d} u}{7 + 2\cos u}
$$
05
Perform another substitution using a trigonometric substitution
Let \(\cos u = \dfrac{t-1/t}{2}\), which implies that \(\sin u \mathrm{d} u = -\frac{\mathrm{d} t}{t^2}\). Rewrite the integral in terms of \(t\):
$$
-\frac{1}{2} \int \frac{\mathrm{d} t/t^2}{7 + 2\left(\frac{t-1/t}{2}\right)}
$$
06
Simplify the expression and integrate
Simplify the expression inside the integral and integrate with respect to \(t\):
$$
-\frac{1}{2} \int \frac{\mathrm{d} t}{t^2 + 6t + 1}
$$
Since this integral is now the form of a rational function, you can solve the integral using partial fraction decomposition or other methods for integrating rational functions. The result will be:
$$
-\frac{1}{2} \left(\frac{2}{\sqrt{5}} \tan ^{-1}\left(\frac{2 t + 6}{\sqrt{5}}\right) + C\right)
$$
07
Replace the substitutions
Replace \(t\) with \(\smash{\frac{1+\cos(u)}{2}}\), and then replace \(u\) with \(2x\):
$$
-\frac{1}{2} \left(\frac{2}{\sqrt{5}} \tan ^{-1}\left(\frac{2 (\frac{1+\cos(2x)}{2}) + 6}{\sqrt{5}}\right) + C\right)
$$
This is the final answer for the given integral.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Substitution
Trigonometric substitution is a technique used in integral calculus to simplify integrals involving trigonometric functions. It's a clever way of converting complex trigonometric expressions into simpler algebraic forms. In the solved problem, the integration begins by employing a fundamental identity for cosine:
- Use the identity \( \cos^2x = \frac{1 + \cos(2x)}{2} \) to rewrite the integrand.
Integration Techniques
Integral calculus has a variety of techniques to solve different kinds of integrals. In this solution, multiple techniques have been employed.
- Initial substitution of \( u = 2x \) to simplify the integral.
- Factor out constants to make the integral look cleaner and easier to evaluate.
- Use of trigonometric substitution, indicating deeper transformation needs for complex trigonometric functions.
Rational Functions
Rational functions in calculus are expressions that can be placed in the form of a ratio of two polynomials. In this solution, the integral was reduced to involve rational functions after substitution:
- This happens after transforming the trigonometric terms into algebraic expressions.
- Specifically, the form becomes \( \frac{1}{t^2 + 6t + 1} \), a familiar form for those working with rational expressions.