Chapter 5: Problem 32
The random variable \(x\) is normally distributed with mean \(\mu=74\) and
standard deviation \(\sigma=8\). Find the indicated probability.
$$P(72
Short Answer
Expert verified
The probability is 0.44 or 44%.
Step by step solution
01
Understand the problem
We need to determine the probability that a random variable following a normal distribution with a mean, \(\mu = 74\), and a standard deviation, \(\sigma = 8\), lies between 72 and 82.
02
Standardize the Random Variable
Convert the variables \(x=72\) and \(x=82\) to their corresponding z-scores using the formula \(z = \frac{x - \mu}{\sigma}\). Calculate:- For \(x = 72\): \(z_{72} = \frac{72 - 74}{8} = -0.25\)- For \(x = 82\): \(z_{82} = \frac{82 - 74}{8} = 1.00\)
03
Use the Standard Normal Distribution Table
Refer to the standard normal distribution table (z-table) to find probabilities corresponding to the z-scores:- For \(z = -0.25\), the probability is approximately 0.4013.- For \(z = 1.00\), the probability is approximately 0.8413.
04
Find the Probability Between the Z-scores
Determine the probability of the random variable being between z-scores \(-0.25\) and \(1.00\) by calculating:\[ P(-0.25 < z < 1.00) = P(z < 1.00) - P(z < -0.25) = 0.8413 - 0.4013 = 0.4400 \]
05
Conclusion
Conclude that the probability that \(72 < x < 82\) is \(0.44\) or 44%.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Deviation
Standard deviation is a key concept in statistics that measures the amount of variation or dispersion in a set of data values. It tells us how spread out the values are from the mean (average) of the dataset.
In a normal distribution, the data is symmetrically distributed around the mean, creating a bell-shaped curve. The standard deviation helps us understand how squeezed or stretched the curve is.
In the given exercise, the standard deviation is \(\sigma = 8\)\, indicating that most of the data points lie within 8 units of the mean.
In a normal distribution, the data is symmetrically distributed around the mean, creating a bell-shaped curve. The standard deviation helps us understand how squeezed or stretched the curve is.
- When the standard deviation is small, the data points are clustered close to the mean.
- When the standard deviation is large, the data points are spread out over a wider range of values.
In the given exercise, the standard deviation is \(\sigma = 8\)\, indicating that most of the data points lie within 8 units of the mean.
Mean
The mean, often referred to as the average, represents the central value of a dataset. It is calculated by adding together all the numbers in the dataset and then dividing by the total number of values.
The mean is \(\mu\) in the context of a normal distribution, and it is the point where the bell-shaped curve peaks. All data points are averaged out around this central value, providing a measure of the data's central tendency.
When mapping probabilities, the mean helps determine how far other values lie from this central point.
The mean is \(\mu\) in the context of a normal distribution, and it is the point where the bell-shaped curve peaks. All data points are averaged out around this central value, providing a measure of the data's central tendency.
- An unbiased estimator of the central location of data.
- Derived from the formula: \(\mu = \rac{sumOfData}{totalNumberOfData}\)
When mapping probabilities, the mean helps determine how far other values lie from this central point.
Z-score
A z-score is a statistic that tells us how many standard deviations a data point is from the mean. It's a crucial tool when working with normal distributions, allowing for standardization of different data points.
The z-score formula is:\[z = \frac{x - \mu}{\sigma}\]where \(x\) is the individual data point, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
\[z_{72} = \frac{72 - 74}{8} = -0.25, \quad z_{82} = \frac{82 - 74}{8} = 1.00\]These z-scores help find probabilities by referring to a z-table, essential for determining probabilities in a normal distribution.
The z-score formula is:\[z = \frac{x - \mu}{\sigma}\]where \(x\) is the individual data point, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
- A z-score of 0 represents the mean itself.
- Positive z-scores indicate data points above the mean.
- Negative z-scores indicate data points below the mean.
\[z_{72} = \frac{72 - 74}{8} = -0.25, \quad z_{82} = \frac{82 - 74}{8} = 1.00\]These z-scores help find probabilities by referring to a z-table, essential for determining probabilities in a normal distribution.