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Show two different ways to state that the means of two populations are equal.

Short Answer

Expert verified
1) \( \mu_1 = \mu_2 \); 2) Null hypothesis \( H_0: \mu_1 = \mu_2 \).

Step by step solution

01

Understand the Concept

Equality of two population means refers to a situation where the average values (means) of the same characteristic in two different groups are the same. This can be evaluated using statistical language or hypothesis testing.
02

State Aspect One - Statistical Notation

The first way to state that the means of two populations are equal is using statistical notation. We denote the means of the two populations as \( \mu_1 \) and \( \mu_2 \). To state that these means are equal, write: \( \mu_1 = \mu_2 \).
03

State Aspect Two - Null Hypothesis

Another way to state the equality of two population means is through hypothesis testing. In hypothesis testing, the statement of equality is formulated as a null hypothesis. This is written as: \( H_0: \mu_1 = \mu_2 \). Here \( H_0 \) denotes the null hypothesis which assumes that there is no difference between the two population means.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Notation
Statistical notation is a concise way of representing complex mathematical statements using symbols and operators. It simplifies the communication of mathematical ideas, especially in statistics and probability theory. When we say two population means are equal using statistical notation, it is denoted as \( \mu_1 = \mu_2 \).
\( \mu_1 \) and \( \mu_2 \) represent the average values of a characteristic from two different populations.
This notation is straightforward and provides a direct mathematical statement of the desired scenario.
Statistical notation is fundamental in statistics as it allows scientists and researchers to express hypotheses and assumptions succinctly.
  • \( \mu_1 \, \text{and} \, \mu_2 \) are symbols representing population means.
  • Equal sign (\( = \)) indicates equality between the two means.
  • This form is used in initial explorations and concept explanations.
Understanding statistical notation helps you decipher complex statistical claims and validate research findings.
Null Hypothesis
The null hypothesis is a fundamental concept in statistics, forming the basis for hypothesis testing. It is a statement used as a starting point for statistical testing, assuming no effect or no difference is present.
In our context, when dealing with the equality of population means, the null hypothesis is stated as \( H_0: \mu_1 = \mu_2 \).
Here, \( H_0 \) denotes the null hypothesis.
The null hypothesis allows us to remain unbiased at the start of scientific testing. Here’s why the null hypothesis is critical:
  • \( H_0 \) provides a standard against which observations can be compared.
  • It assumes that any observed effect or difference is due to random chance unless proven otherwise.
  • The structure of \( H_0 \) focuses testing efforts on proving or disproving assumed equality or effects between variables.
Utilizing the null hypothesis gives a standardized way to approach hypothesis testing. It ensures that researchers start with a presumption that the effect they are testing doesn't exist until there's enough evidence to claim otherwise.
Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions based on data.
It involves testing an initial assumed statement, known as the null hypothesis, against another statement called the alternative hypothesis.
The core aim of hypothesis testing in the context of equality of means is to evaluate whether there truly is no difference between the two population means, or if any difference observed is due to genuine effects.
  • The null hypothesis \( H_0 \) is assumed true until there is substantive evidence to reject it.
  • An alternate hypothesis \( H_a \) – the opposite of the null hypothesis – usually suggests a difference or effect.
  • The process involves calculating a test statistic from sample data and comparing it against a critical value or using a p-value.
  • If the test results are significant, \( H_0 \) is rejected in favor of \( H_a \).
Hypothesis testing is essential in decision-making and research, as it allows scientists to make informed conclusions about population parameters based on sample data.

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Most popular questions from this chapter

For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. High School Graduation Rates The overall U.S. public high school graduation rate is \(73.4 \% .\) For Pennsylvania it is \(83.5 \%\) and for Idaho \(80.5 \%-\mathrm{a}\) difference of \(3 \%\). Random samples of 1200 students from each state indicated that 980 graduated in Pennsylvania and 940 graduated in Idaho. At the 0.05 level of significance, can it be concluded that there is a difference in the proportions of graduating students between the states?

Heights of 9 -Year-Olds At age 9 the average weight \((21.3 \mathrm{kg})\) and the average height \((124.5 \mathrm{cm})\) for both boys and girls are exactly the same. A random sample of 9 -year-olds yielded these results. At \(\alpha=0.05,\) do the data support the given claim that there is a difference in heights? $$ \begin{array}{lcc}{} & {\text { Boys }} & {\text { Girls }} \\ \hline \text { Sample size } & {60} & {50} \\ {\text { Mean height, } \mathrm{cm}} & {123.5} & {126.2} \\ {\text { Population variance }} & {98} & {120}\end{array} $$

For Exercises 9 through \(24,\) perform the following steps. Assume that all variables are normally distributed. a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Reading Program Summer reading programs are very popular with children. At the Citizens Library, Team Ramona read an average of 23.2 books with a standard deviation of \(6.1 .\) There were 21 members on this team. Team Beezus read an average of 26.1 books with a standard deviation of \(2.3 .\) There 23 members on this team. Did the variances of the two teams differ? Use \(\alpha=0.05 .\)

For Exercises 9 through \(24,\) perform the following steps. Assume that all variables are normally distributed. a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Carbohydrates in Candy The number of grams of carbohydrates contained in 1 -ounce servings of randomly selected chocolate and nonchocolate candy is shown. Is there sufficient evidence to conclude that there is a difference between the variation in carbohydrate content for chocolate and nonchocolate candy? Use \(\alpha=0.10 .\) $$ \begin{array}{llllllll}{\text { Chocolate }} & {29} & {25} & {17} & {36} & {41} & {25} & {32} & {29} \\ {} & {38} & {34} & {24} & {27} & {29} & {} & {} \\\ {\text { Nonchocolate }} & {41} & {41} & {37} & {29} & {30} & {38} & {39} & {10} \\ {} & {29} & {55} & {29} & {}\end{array} $$

For these exercises, perform each of these steps. Assume that all variables are normally or approximately normally distributed. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified and assume the variances are unequal. Tax-Exempt Properties A tax collector wishes to see if the mean values of the tax-exempt properties are different for two cities. The values of the tax- exempt properties for the two random samples are shown. The data are given in millions of dollars. At \(\alpha=0.05,\) is there enough evidence to support the tax collector's claim that the means are different? $$ \begin{array}{cccc|cccc}{} & {\text { City } \mathbf{A}} & {} & {} & {} & {\text { City } \mathbf{B}} & {} & {} \\ \hline 113 & {22} & {14} & {8} & {82} & {11} & {5} & {15} \\ {25} & {23} & {23} & {30} & {295} & {50} & {12} & {9} \\ {44} & {11} & {19} & {7} & {12} & {68} & {81} & {2} \\ {31} & {19} & {5} & {2} & {} & {20} & {16} & {4} & {5}\end{array} $$

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