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The average prison sentence for a person convicted of second-degree murder is 15 years. If the sentences are normally distributed with a standard deviation of 2.1 years, find these probabilities: a. A prison sentence is greater than 18 years. b. A prison sentence is less than 13 years.

Short Answer

Expert verified
a. 7.64%; b. 17.11%.

Step by step solution

01

Identify Given Information

We have a normal distribution with a mean \( \mu = 15 \) years and a standard deviation \( \sigma = 2.1 \) years for the sentences. We are asked to find probabilities for sentences greater than 18 years and less than 13 years.
02

Calculate the Z-score for Part a

The Z-score formula is \( Z = \frac{X - \mu}{\sigma} \). For \( X = 18 \), the Z-score is \( Z = \frac{18 - 15}{2.1} = \frac{3}{2.1} \approx 1.43 \).
03

Find Probability for Part a

Using the Z-score table, find the probability that Z is less than 1.43. The table gives a cumulative probability up to 1.43, which is approximately 0.9236. The probability of a sentence greater than 18 years is \( 1 - 0.9236 = 0.0764 \) or 7.64%.
04

Calculate the Z-score for Part b

Using the same Z-score formula, for \( X = 13 \), the Z-score is \( Z = \frac{13 - 15}{2.1} = \frac{-2}{2.1} \approx -0.95 \).
05

Find Probability for Part b

Using the Z-score table, find the probability that Z is less than -0.95, which is approximately 0.1711. Therefore, the probability that a sentence is less than 13 years is 17.11%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
Understanding the Z-score is crucial when dealing with normal distribution. The Z-score is a measure that describes a value's position relative to the mean of a group of values. In simple terms, it tells us how many standard deviations an element is from the mean.

The formula used to calculate the Z-score is: \[Z = \frac{X - \mu}{\sigma}\]
  • \(X\) is the value you're analyzing
  • \(\mu\) is the mean of the data set
  • \(\sigma\) is the standard deviation
When using this formula, a Z-score of 0 indicates that the data point's score is identical to the mean score. A Z-score of +1.43, for example, indicates a point that is 1.43 standard deviations above the mean.
probability calculation
Probability calculation in the context of normal distribution involves finding the likelihood that a random variable falls within a certain range. In scenarios like the prison sentence example, we want to determine two probabilities:
  • The probability that a sentence is greater than 18 years
  • The probability that a sentence is less than 13 years
By calculating the Z-score for each case, we can then use a Z-table, or a standard normal distribution table, to find the cumulative probability associated with those Z-scores.

The key here is understanding that this probability is a measure between 0 and 1, often expressed as a percentage, which shows how likely it is for the random variable to be less than or equal to a certain value.
cumulative probability
Cumulative probability gives the probability that a random variable will take a value less than or equal to a specific value. This type of probability calculation becomes particularly handy when comparing random variables against a threshold.

In the context of our normal distribution, cumulative probability helps us determine the likelihood of a prison sentence being under a certain number of years. For example, when the calculated Z-score for a sentence less than 13 years fell at approximately -0.95, we looked up this score in the Z-table and found the cumulative probability to be about 0.1711, or 17.11%. This informs us that there's a 17.11% chance a sentence would be 13 years or shorter.
standard deviation
Standard deviation is a measure of variability or dispersion within a set of data. It shows how much individual data points differ from the mean value. A low standard deviation indicates that the data points tend to be close to the mean, whereas a high standard deviation indicates that they are spread out over a wide range.

In the example concerning prison sentences for second-degree murder, the standard deviation is 2.1 years. This value provides insights into how much prison sentence lengths typically vary from the average sentence of 15 years.
  • Helps identify the 'spread' in your data set
  • Vital in calculating the Z-score
  • Integral to understanding the variability in a normal distribution
Understanding standard deviation thus enhances one's grasp of the data's overall distribution and variability.

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