/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 \(z_{0}\) is the statistical not... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(z_{0}\) is the statistical notation for an unknown z value. It serves that same function as \(x\) does in an algebraic equation. Find \(z_{0}\) such that \(P\left(-z_{0}

Short Answer

Expert verified
The value of \( z_0 \) is approximately 1.175.

Step by step solution

01

Understand the Problem

The goal is to find the value of \( z_0 \) such that the probability that the random variable \( z \) is within the range \(-z_0\) to \( z_0\) equals 0.76. This implies \( P(-z_0 < z < z_0) = 0.76 \).
02

Use Properties of the Standard Normal Distribution

For a standard normal distribution, the total area under the curve is 1. The interval \(-z_0\) to \(z_0\) contains 76% of this area, which leaves 24% for the two tails (12% in each tail) outside the interval \(-z_0 < z < z_0\).
03

Standard Normal Distribution Properties

Since the normal distribution is symmetric, \( P(z < -z_0) = P(z > z_0) = 0.12 \). Thus, \( P(z < z_0) \) must be equal to \(0.76/2 + 0.12 = 0.88\).
04

Use Z-Table or Normal Distribution Calculator

Using a Z-table, find the \(z\) value which corresponds to an area of 0.88 to the left of it. This \(z\) value is your \(z_0\). Check the Z-table and find that \(z = 1.175\) approximately.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Score
Z-scores are a fundamental concept in statistics, particularly when dealing with probability distributions like the standard normal distribution. But what is a z-score? Simply put, a z-score tells us how many standard deviations an element is from the mean of a distribution. This can be extremely useful when trying to understand how likely or unlikely a particular observation is within the context of the entire distribution.The formula for finding a z-score is:\[ z = \frac{(X - \mu)}{\sigma} \]Where:- \( X \) is the value we're looking at,- \( \mu \) is the mean of the distribution,- \( \sigma \) is the standard deviation of the distribution.Z-scores help us find probabilities in a standard normal distribution, which has a mean of 0 and a standard deviation of 1. This makes it easier to calculate probabilities without needing to worry about the specific characteristics of a distribution.
Decoding Probability
Probability is a measure that calculates the likelihood of a given event occurring. In statistics, particularly in the context of a normal distribution, probability helps us understand the chances of variables falling within certain ranges.In our exercise, we're looking at the probability within the interval \(-z_0 < z < z_0\), which is given as 0.76. This means there is a 76% chance that the variable z will fall between these two points.To find this probability on a standard normal distribution curve:- The entire area under the curve equals 1. - The area that corresponds to our probability of interest is twice the area from one tail, as the normal curve is symmetrical.- Given 76% in the middle, 24% is spread across the tails (12% each).Thus, knowing probability allows us to use standard statistical tools, like Z-tables, to pinpoint exact values of z-scores that relate to specified probabilities.
Statistical Notation Simplified
Statistical notation can initially seem daunting, but it provides a clean and universal method to express statistical ideas and calculations. Let’s demystify the basic elements used in the exercise.- \( z_0 \): In statistical notation, \( z_0 \) is our unknown z-score value that we are trying to find based on known probabilities. It functions similarly to finding an unknown variable in algebra.- \( P(-z_0 < z < z_0) = 0.76 \): This notation means we're interested in the probability that z is between \(-z_0\) and \(z_0\), and this probability equals 0.76, or 76%.Using statistical notation helps in clearly and concisely communicating complex statistical concepts. It can convey a lot of information in an organized, standardized way, peeling away any ambiguity, which is crucial when solving problems involving probability and z-scores.

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Most popular questions from this chapter

The average commute to work (one way) is 25 minutes according to the 2005 American Community Survey. If we assume that commuting times are normally distributed and that the standard deviation is 6.1 minutes, what is the probability that a randomly selected commuter spends more than 30 minutes commuting one way? Less than 18 minutes?

Procter & Gamble reported that an American family of four washes an average of 1 ton (2000 pounds) of clothes each year. If the standard deviation of the distribution is 187.5 pounds, find the probability that the mean of a randomly selected sample of 50 families of four will be between 1980 and 1990 pounds.

College students often make up a substantial portion of the population of college cities and towns. State College, Pennsylvania, ranks first with 71.1% of its population made up of college students. What is the probability that in a random sample of 150 people from State College, more than 50 are not college students?

The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 52,145, find the probability that on a randomly selected day, the jail population is a. Greater than 750,000 b. Between 600,000 and 700,000

The average teacher's salary in Connecticut (ranked first among states) is \(\$ 57,337\). Suppose that the distribution of salaries is normal with a standard deviation of \(\$ 7500 .\) a. What is the probability that a randomly selected teacher makes less than \(\$ 52,000\) per year? b. If we sample 100 teachers' salaries, what is the probability that the sample mean is less than \(\$ 56,000 ?\)

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