Chapter 6: Problem 56
\(z_{0}\) is the statistical notation for an unknown z value. It serves that
same function as \(x\) does in an algebraic equation.
Find \(z_{0}\) such that \(P\left(-z_{0}
Short Answer
Expert verified
The value of \( z_0 \) is approximately 1.175.
Step by step solution
01
Understand the Problem
The goal is to find the value of \( z_0 \) such that the probability that the random variable \( z \) is within the range \(-z_0\) to \( z_0\) equals 0.76. This implies \( P(-z_0 < z < z_0) = 0.76 \).
02
Use Properties of the Standard Normal Distribution
For a standard normal distribution, the total area under the curve is 1. The interval \(-z_0\) to \(z_0\) contains 76% of this area, which leaves 24% for the two tails (12% in each tail) outside the interval \(-z_0 < z < z_0\).
03
Standard Normal Distribution Properties
Since the normal distribution is symmetric, \( P(z < -z_0) = P(z > z_0) = 0.12 \). Thus, \( P(z < z_0) \) must be equal to \(0.76/2 + 0.12 = 0.88\).
04
Use Z-Table or Normal Distribution Calculator
Using a Z-table, find the \(z\) value which corresponds to an area of 0.88 to the left of it. This \(z\) value is your \(z_0\). Check the Z-table and find that \(z = 1.175\) approximately.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Z-Score
Z-scores are a fundamental concept in statistics, particularly when dealing with probability distributions like the standard normal distribution. But what is a z-score? Simply put, a z-score tells us how many standard deviations an element is from the mean of a distribution. This can be extremely useful when trying to understand how likely or unlikely a particular observation is within the context of the entire distribution.The formula for finding a z-score is:\[ z = \frac{(X - \mu)}{\sigma} \]Where:- \( X \) is the value we're looking at,- \( \mu \) is the mean of the distribution,- \( \sigma \) is the standard deviation of the distribution.Z-scores help us find probabilities in a standard normal distribution, which has a mean of 0 and a standard deviation of 1. This makes it easier to calculate probabilities without needing to worry about the specific characteristics of a distribution.
Decoding Probability
Probability is a measure that calculates the likelihood of a given event occurring. In statistics, particularly in the context of a normal distribution, probability helps us understand the chances of variables falling within certain ranges.In our exercise, we're looking at the probability within the interval \(-z_0 < z < z_0\), which is given as 0.76. This means there is a 76% chance that the variable z will fall between these two points.To find this probability on a standard normal distribution curve:- The entire area under the curve equals 1. - The area that corresponds to our probability of interest is twice the area from one tail, as the normal curve is symmetrical.- Given 76% in the middle, 24% is spread across the tails (12% each).Thus, knowing probability allows us to use standard statistical tools, like Z-tables, to pinpoint exact values of z-scores that relate to specified probabilities.
Statistical Notation Simplified
Statistical notation can initially seem daunting, but it provides a clean and universal method to express statistical ideas and calculations. Let’s demystify the basic elements used in the exercise.- \( z_0 \): In statistical notation, \( z_0 \) is our unknown z-score value that we are trying to find based on known probabilities. It functions similarly to finding an unknown variable in algebra.- \( P(-z_0 < z < z_0) = 0.76 \): This notation means we're interested in the probability that z is between \(-z_0\) and \(z_0\), and this probability equals 0.76, or 76%.Using statistical notation helps in clearly and concisely communicating complex statistical concepts. It can convey a lot of information in an organized, standardized way, peeling away any ambiguity, which is crucial when solving problems involving probability and z-scores.