Chapter 6: Problem 27
Find the probabilities for each, using the standard normal distribution. \(P(0< z<0.95)\)
Short Answer
Expert verified
The probability is approximately 0.3289.
Step by step solution
01
Understand the Problem Context
We need to find the probability that a standard normal random variable, denoted as \( z \), falls between 0 and 0.95. The standard normal distribution has a mean of 0 and a standard deviation of 1.
02
Use the Standard Normal Table
The standard normal table, or \( z \)-table, is used to find the probability that \( z \) is less than a certain value. First, find \( P(z < 0.95) \) using the table, and note that it gives the cumulative probability up to 0.95.
03
Look Up the Z-value
Using the \( z \)-table, locate the row for the first decimal of 0.9 and the column for the second decimal 0.05. This will give us \( P(z < 0.95) \). From the table, \( P(z < 0.95) \approx 0.8289 \).
04
Compute the Desired Probability
The probability that \( z \) falls between 0 and 0.95 is \( P(0 < z < 0.95) = P(z < 0.95) - P(z < 0) \). We know \( P(z < 0) = 0.5 \) from the symmetry of the standard normal distribution.
05
Calculate the Final Result
Subtract \( P(z < 0) = 0.5 \) from \( P(z < 0.95) \) to find the probability: \[ P(0 < z < 0.95) = 0.8289 - 0.5 = 0.3289 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-table
A "z-table" is a critical tool in statistics for finding probabilities associated with the standard normal distribution. This table lists the cumulative probability of a standard normal random variable, denoted as \( z \), being less than a specific value. When you hear about the "standard normal distribution," this is a normal distribution with a mean of 0 and a standard deviation of 1. By consulting a z-table, one can determine the likelihood of a random variable falling below a particular \( z \)-score.
To use a z-table effectively, you need to understand two numbers:
To use a z-table effectively, you need to understand two numbers:
- The \( z \)-score, which is typically provided in a problem.
- The cumulative probability corresponding to this \( z \)-score, which the table provides.
Normal Distribution
The "normal distribution" is one of the most common probability distributions in statistics. Sometimes called a "bell curve," it describes how data is spread over a range of values. Most real-world data, from test scores to heights, often follows this pattern, with a large percentage falling around the mean and fewer numbers towards the extremes.
A normal distribution is symmetrical, meaning that the left and the right sides of the curve are mirror images. It is defined by two parameters:
A normal distribution is symmetrical, meaning that the left and the right sides of the curve are mirror images. It is defined by two parameters:
- The "mean" (average), which determines the center of the distribution.
- The "standard deviation," which reflects how spread out the values are around the mean.
Probability Calculations
"Probability calculations" using the standard normal distribution involve determining the likelihood of a random variable falling within a specific range. The cumulative distribution function (CDF) provided by the z-table tells us the probability that a standard normal random variable is less than a certain value.
For example, if we want to know the probability that a standard normal variable \( z \) is between 0 and 0.95, we start by finding \( P(z < 0.95) \) from the z-table. This is the area under the curve to the left of 0.95. Next, we subtract \( P(z < 0) \), which is 0.5 due to the symmetry of the distribution, from \( P(z < 0.95) \). This subtraction gives us the desired probability for the range.
For example, if we want to know the probability that a standard normal variable \( z \) is between 0 and 0.95, we start by finding \( P(z < 0.95) \) from the z-table. This is the area under the curve to the left of 0.95. Next, we subtract \( P(z < 0) \), which is 0.5 due to the symmetry of the distribution, from \( P(z < 0.95) \). This subtraction gives us the desired probability for the range.
- Step 1: Use the z-table to find \( P(z < 0.95) \).
- Step 2: Remember \( P(z < 0) = 0.5 \) for the standard normal distribution.
- Step 3: Calculate the difference, \( P(0 < z < 0.95) = P(z < 0.95) - P(z < 0) \).