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Find the area under the standard normal distribution curve. $$ \text { To the left of } z=-0.75 $$

Short Answer

Expert verified
The area to the left of \( z = -0.75 \) is approximately 0.2266.

Step by step solution

01

Understanding the Problem

The problem asks us to find the area under the standard normal distribution curve to the left of \( z = -0.75 \). This is equivalent to finding the cumulative probability up to \( z = -0.75 \).
02

Using the Standard Normal Distribution Table

To find the area under the curve to the left of \( z = -0.75 \), we refer to the standard normal distribution table (z-table) which provides cumulative probabilities for z-values. Locate \(-0.7\) in the leftmost column and \(0.05\) at the top row of the table.
03

Finding the Cumulative Probability

Find the intersection of the row \(-0.7\) and the column \(0.05\) in the standard normal distribution table. The value you find is the cumulative probability for \( z = -0.75 \).
04

Interpreting the Result

The standard normal distribution table typically gives the cumulative probability for a given z-value. For \( z = -0.75 \), the table should show approximately \(0.2266\). This means 22.66% of the distribution lies to the left of \( z = -0.75 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Table
A z-table, also known as a standard normal distribution table, is a chart that helps in finding the probability that a statistic is less than a given z-value. The z-table displays cumulative probabilities, which represent the area under the standard normal curve up to a certain z-value. When you look at a z-table, the numbers on the leftmost column represent the whole number and the first decimal place of a z-value. Meanwhile, the numbers on the top row correspond to the second decimal place of the z-value. To use the z-table effectively:
  • Identify the z-value you're interested in. In our example, it's \( z = -0.75 \).
  • Find the row with \( -0.7 \) and locate the column under \( 0.05 \).
  • The intersection gives the cumulative probability for \( z = -0.75 \).
It's important to understand that z-tables typically reflect cumulative probabilities from the mean of the standard normal distribution, which is zero, up to the z-value of interest.
What is Cumulative Probability?
Cumulative probability is a measure used in statistics to find the probability that a random variable falls within a certain range of values. When dealing with the standard normal distribution, cumulative probability specifically refers to the probability that a z-score in question is less than a particular value. In other words, for a given z-value, cumulative probability tells us how much of the distribution lies to the left of that score.

In our problem with \( z = -0.75 \), the cumulative probability shows the likelihood of finding a value from the distribution that is equal to or less than \( -0.75 \). Calculated by integrating under the curve up to the specific z-score, cumulative probability allows us to determine how extreme a value is relative to the whole data set. We discovered that approximately 22.66% of the dataset is located to the left of \( z = -0.75 \). This gives us valuable insight into the position and rarity of the z-score within the distribution.
How to Determine the Z-Value?
The z-value, also known as a z-score, is a statistical measure that describes a value's position in terms of standard deviations from the mean of the distribution. If you know the mean and standard deviation of the data, you can calculate the z-value with the formula:\[ z = \frac{{X - \mu}}{{\sigma}} \]where \( X \) is the value in the dataset, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.

The z-value helps compare different data points across different normal distributions by converting to standardized units. Remember that negative z-values indicate points below the mean, while positive ones are above it. Using a z-value like \( z = -0.75 \), enables the determination of cumulative probabilities via z-tables, as it standardizes the discussion regardless of the original scale of measurement. This function is particularly useful in comparing scores across different scales or distributions.

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Most popular questions from this chapter

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