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91Ó°ÊÓ

For Exercises 19 through 26, construct a probability distribution for the data and draw a graph for the distribution. Item Selection The probabilities that a customer se- lects \(1,2,3,4,\) and 5 items at a convenience store are \(0.32,0.12,0.23,0.18,\) and \(0.15,\) respectively.

Short Answer

Expert verified
Construct a table and a bar graph for the provided probabilities; ensure their sum is 1.

Step by step solution

01

Understand the Problem

We are provided with a set of probabilities corresponding to selecting different numbers of items at a convenience store. We need to construct a probability distribution table and a graph.
02

Construct the Probability Distribution Table

We list the number of items (1, 2, 3, 4, 5) and their corresponding probabilities.\[\begin{array}{c|c}\text{Number of Items} & \text{Probability} \\hline1 & 0.32 \2 & 0.12 \3 & 0.23 \4 & 0.18 \5 & 0.15 \\end{array}\]
03

Verify Total Probability

Ensure that the sum of probabilities is 1. Calculate: \(0.32 + 0.12 + 0.23 + 0.18 + 0.15 = 1.00\). This confirms that the distribution is valid.
04

Draw the Graph of the Distribution

Use a bar graph to represent the probability distribution. Label the x-axis with the number of items (1 to 5) and the y-axis with the probability values. Draw bars for each item with heights corresponding to their probabilities: 0.32, 0.12, 0.23, 0.18, and 0.15 respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Table
A probability table is a simple yet powerful tool used to represent a probability distribution. In this case, the table lists the number of items a customer might select at a convenience store and their corresponding probabilities. Each row in the table represents a potential outcome (the number of items selected) and its likelihood.

Creating a probability table involves two key components:
  • The first column lists each possible outcome, such as the number of items selected: 1, 2, 3, 4, and 5.
  • The second column lists the probability of each outcome occurring, given here as 0.32, 0.12, 0.23, 0.18, and 0.15.
The probability table concisely shows the relationship between each event and its probability, making it easier to visualize and understand the data.

This structured approach ensures that students can easily follow and apply the information, laying the groundwork for deeper comprehension of probability concepts.
Bar Graph
A bar graph is a visual representation of data that shows comparisons among different categories. Here, we're using a bar graph to display the probability distribution for the number of items a customer might select at a convenience store.

To construct a proper bar graph, follow these steps:
  • Label the x-axis with the categorical variable, which in this case are the number of items (1 through 5).
  • Label the y-axis with the probability values, ensuring the scale accommodates the probabilities given (up to 0.32).
  • For each number of items, draw a bar whose height represents its probability: 0.32 for 1 item, 0.12 for 2 items, 0.23 for 3 items, 0.18 for 4 items, and 0.15 for 5 items.
Bar graphs make it easier to compare the probabilities of various outcomes at a glance. They serve as a visual complement to the probability table, providing another perspective that helps to solidify understanding.
Sum of Probabilities
The sum of probabilities is a critical concept in probability theory, stating that the total probability for all possible outcomes of a random experiment must equal 1. This principle ensures that all outcomes have been accounted for and confirms the validity of the probability distribution.

When dealing with the probability of selecting items at a convenience store, this translates to adding up the probabilities of selecting 1, 2, 3, 4, or 5 items: \[0.32 + 0.12 + 0.23 + 0.18 + 0.15 = 1.00\]Checking that the sum equals 1 is not only a mathematical necessity but also a good practice to verify the correctness of a probability distribution.

By ensuring the sum of probabilities is 1, we confirm that we have a complete and valid representation of all possible outcomes in the data set.

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Most popular questions from this chapter

Blood Type About 4% of the citizens of the United States have type AB blood. If an agency needed type AB blood and donors came in at random, find the average number of donors that would be needed to get a person with type AB blood. The mean of a geometric distribution is \(\mu=1 / p,\) and the standard deviation is \(\sigma=\sqrt{q / p^{2}},\) where \(p=\) the probability of the outcome and \(q=1-p\). Use these formulas for Exercises \(31-34\).

Tossing Coins Find the mean, variance, and standard deviation for the number of heads when 10 coins are tossed.

Federal Government Employee E-mail Use It has been reported that 83% of federal government employees use e-mail. If a sample of 200 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail.

Explain the difference between a discrete and a continuous random variable.

Another type of problem that can be solved uses what is called the negative binomial distribution, which is a generalization of the binomial distribution. In this case, it tells the average number of trials needed to get k successes of a binomial experiment. The formula is $$ \mu=\frac{k}{p} $$ $$ \begin{array}{c}{\text { where } k=\text { the number of successes }} \\\ {p=\text { the probability of a success }}\end{array} $$ Use this formula for Exercises 27–30. Drawing Cards Cards are drawn at random from a deck and replaced after each draw. Find the average number of cards that would be drawn to get 4 face cards.

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