/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Selecting a Letter of the Alphab... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Selecting a Letter of the Alphabet If 3 letters of the alphabet are selected at random, find the probability of getting at least 1 letter \(\mathrm{x}\). Letters can be used more than once. Would you consider this event likely to happen? Explain your answer.

Short Answer

Expert verified
The probability is approximately 0.111, suggesting it is not likely to happen.

Step by step solution

01

Determine Total Possible Outcomes

There are 26 letters in the alphabet and each letter can be selected more than once. Therefore, the total number of possible outcomes when selecting 3 letters is given by \(26^3\) because for each letter position you have 26 choices. Calculating this gives: \(26^3 = 17576\).
02

Determine Favorable Outcomes

To find favorable outcomes, calculate the probability of selecting at least one 'x'. It's easier to use the complement rule, finding the probability of not selecting 'x' at all and subtracting this from 1. Without 'x', you have 25 other choices for each selection, giving \(25^3\) ways. So, \(25^3 = 15625\).
03

Calculate Complement Probability

The probability of selecting no 'x' is the number of no-'x' outcomes over total outcomes: \(\frac{15625}{17576}\).
04

Calculate Probability of at Least One 'x'

Subtract the complement probability from 1 to find the probability of getting at least one 'x'. Thus, \( P(\text{at least one 'x'}) = 1 - \frac{15625}{17576} = \frac{1951}{17576} \approx 0.111\).
05

Determine Likelihood

A probability of approximately 0.111 means there is an 11.1% chance of selecting at least one 'x'. Since this probability is relatively low, we would not consider this event likely to happen.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complement Rule
The complement rule is a powerful concept in probability that helps in finding the probability of an event by considering the opposite event, or its "complement." Instead of directly calculating the probability of a complex event, it's often easier to find what we don't want, and then subtract that from 1.

In this exercise, we need to determine the probability of selecting at least one 'x' when choosing 3 letters from the alphabet. Rather than directly assessing all scenarios where 'x' might appear, we consider the simpler complement: choosing zero 'x's. If we calculate how often 'x' isn't chosen at all and subtract that probability from 1, we get the desired probability of at least one 'x'. This way, even if the direct calculation is cumbersome, the complement rule simplifies our task effectively.
Favorable Outcomes
Favorable outcomes refer to the specific results we are interested in when calculating probability. They are the instances that meet our conditions for "success."

In this context, favorable outcomes mean selecting at least one 'x' out of the 3 letters picked. Initially, it can seem intricate to directly list every scenario where an 'x' appears. However, by leveraging the complement rule, we look at picking "no 'x's" first, which becomes our focus to determine unsuccessful attempts. By subtracting these from the total, the remaining options are deemed favorable. Hence, favorable outcomes are all possibilities minus the times when there's no 'x'. It simplifies the process considerably.
Total Possible Outcomes
To find the probability of any event, determining the total possible outcomes is crucial. This represents all conceivable results when a process or experiment is carried out.

With our problem, choosing 3 letters offers numerous possibilities. Since each of the 3 letters can individually be any of the 26 letters in the alphabet, and each choice is independent, we calculate the total possibilities by raising 26 to the power of 3. Mathematically, this becomes \[26^3 = 17576\].This number provides the basis for formulating probabilities, knowing that any specific scenario (or group of scenarios) would be divided by this figure.
Unlikely Events
Unlikely events in probability are those with a low chance of occurring. When we compute a probability and find it to be small, typically less than 20%, it suggests the event is unlikely.

After using the complement rule and calculating all probabilities, we found the probability of selecting at least one 'x' to be approximately 0.111, or 11.1%. This indicates that in a random selection from the alphabet, choosing one or more 'x's is not very probable. Such a low probability suggests it's an unlikely event, meaning it wouldn't typically happen unless numerous selections are made. Understanding this helps in setting realistic expectations in various scenarios where chance plays a role.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show Programs Three bands and two comics are performing for a student talent show. How many different programs (in terms of order) can be arranged? How many if the comics must perform between bands?

$$ \begin{array}{l}{\text { Odds Odds are used in gambling games to make them }} \\\ {\text { fair. For example, if you rolled a die and won every }} \\\ {\text { time you rolled a } 6, \text { then you would win on average }} \\\ {\text { once every } 6 \text { times. So that the game is fair, the odds of }} \\ {5 \text { to } 1 \text { are given. This means that if you bet } \$ 1 \text { and won, }} \\ {\text { you could win } \$ 5 . \text { On average, you would win } \$ 5 \text { once }} \\ {\text { in } 6 \text { rolls and lose } \$ 1 \text { on the other } 5 \text { rolls-hence the }} \\ {\text { term fair game. }}\end{array} $$ $$ \begin{array}{l}{\text { In most gambling games, the odds given are not fair. }} \\ {\text { For example, if the odds of winning are really } 20 \text { to } 1,} \\ {\text { the house might offer } 15 \text { to } 1 \text { in order to make a profit. }} \\ {\text { Odds can be expressed as a fraction or as a ratio, }} \\ {\text { such as } \frac{5}{1}, 5: 1, \text { or } 5 \text { to } 1 . \text { Odds are computed in favor }} \\ {\text { of the event or against the event. The formulas for }} \\ {\text { odds are }}\end{array} $$ $$ \begin{array}{l}{\text { Odds in favor }=\frac{P(E)}{1-P(E)}} \\ {\text { Odds against }=\frac{P(\bar{E})}{1-P(\bar{E})}}\end{array} $$ In the die example, $$ \begin{array}{c}{\text { Odds in favor of a } 6=\frac{\frac{1}{6}}{\frac{5}{6}}=\frac{1}{5} \text { or } 1: 5} \\ {\text { Odds against a } 6=\frac{\frac{5}{6}}{\frac{1}{6}}=\frac{5}{1} \text { or } 5: 1}\end{array} $$ Find the odds in favor of and against each event. a. Rolling a die and getting a 2 b. Rolling a die and getting an even number c. Drawing a card from a deck and getting a spade d. Drawing a card and getting a red card e. Drawing a card and getting a queen f. Tossing two coins and getting two tails g. Tossing two coins and getting exactly one tail

Tossing a Coin and Rolling a Die A coin is tossed; if it falls heads up, it is tossed again. If it falls tails up, a die is rolled. Draw a tree diagram and determine the outcomes.

Medications for Depression A researcher wishes her patients to try a new medicine for depression. How many different ways can she select 5 patients from 50 patients?

2014 Top Albums (Based on U.S. sales) Of all of the U.S. album sales 1989 (Taylor Swift) accounted for \(25 \%\) of sales, Frozen (Various Artists) accounted for \(24.1 \%\) of sales, In the Lonely Hour (Sam Smith) accounted for \(8.2 \%\) of sales. What is the probability that a randomly selected album was something other than these three albums?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.