Chapter 4: Problem 33
Evaluate each expression. $$ \begin{array}{ll}{a . _{5} \mathrm{C}_{2}} & { d. _{6} \mathrm{C}_{2}} \\\ {\text b._{3} \mathrm{C}_{3}} & {\text e._{6} \mathrm{C}_{4}} \\ {\text c._{7} \mathrm{C}_{4}}\end{array} $$
Short Answer
Expert verified
\( _{5}C_{2} = 10, \ _{3}C_{3} = 1,\ _{7}C_{4} = 35,\ _{6}C_{2} = 15,\ _{6}C_{4} = 15 \).
Step by step solution
01
Understanding Combinations
The combination formula is used to determine the number of ways to choose a subset of items from a larger set, where the order of selection does not matter. The formula for calculating combinations is given by: \[ _{n}C_{r} = \frac{n!}{r!(n-r)!} \]where \( n \) is the total number of items, \( r \) is the number of items to choose, and \( ! \) denotes factorial, which is the product of all positive integers up to that number.
02
Calculate _{5}C_{2}
Using the combination formula, we have:\[ _{5}C_{2} = \frac{5!}{2!(5-2)!} \]Start by calculating the factorials:- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)- \( 2! = 2 \times 1 = 2 \)- \( (5-2)! = 3! = 3 \times 2 \times 1 = 6 \)Substitute these into the formula:\[ _{5}C_{2} = \frac{120}{2 \times 6} = \frac{120}{12} = 10 \]
03
Calculate _{3}C_{3}
For \( _{3}C_{3} \):\[ _{3}C_{3} = \frac{3!}{3!(3-3)!} \]Factorials are:- \( 3! = 6 \)- \( 0! = 1 \)Substitute into the formula:\[ _{3}C_{3} = \frac{6}{6 \times 1} = 1 \]
04
Calculate _{7}C_{4}
Using the combination formula, we have:\[ _{7}C_{4} = \frac{7!}{4!(7-4)!} \]Calculate factorials:- \( 7! = 5040 \)- \( 4! = 24 \)- \( 3! = 6 \)Substitute these into the formula:\[ _{7}C_{4} = \frac{5040}{24 \times 6} = \frac{5040}{144} = 35 \]
05
Calculate _{6}C_{2}
Apply the combination formula:\[ _{6}C_{2} = \frac{6!}{2!(6-2)!} \]Factorials are:- \( 6! = 720 \)- \( 2! = 2 \)- \( 4! = 24 \)Substitute these to find:\[ _{6}C_{2} = \frac{720}{2 \times 24} = \frac{720}{48} = 15 \]
06
Calculate _{6}C_{4}
Since \( _{n}C_{r} = _{n}C_{n-r} \), use \( _{6}C_{2} \) from Step 5:\[ _{6}C_{4} = _{6}C_{2} = 15 \]
07
Final Compilation of Results
Based on the calculations above, here are the results for each expression:- \( _{5}C_{2} = 10 \)- \( _{3}C_{3} = 1 \)- \( _{7}C_{4} = 35 \)- \( _{6}C_{2} = 15 \)- \( _{6}C_{4} = 15 \)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factorials
Factorials are a fundamental concept in combinatorial mathematics, often denoted by the symbol "!". A factorial of a non-negative integer, say \( n \), is the product of all positive integers less than or equal to \( n \). Therefore, to calculate \( n! \) (read as "n factorial"), you multiply all whole numbers from \( n \) down to 1.
For instance, \( 5! \) is calculated as \( 5 \times 4 \times 3 \times 2 \times 1 = 120 \). This operation helps determine the number of ways to arrange \( n \) objects in a sequence. Factorials are heavily used in combinations and permutations in mathematics because they account for the different possible arrangements of a set. Here are some easy-to-remember properties of factorials:
For instance, \( 5! \) is calculated as \( 5 \times 4 \times 3 \times 2 \times 1 = 120 \). This operation helps determine the number of ways to arrange \( n \) objects in a sequence. Factorials are heavily used in combinations and permutations in mathematics because they account for the different possible arrangements of a set. Here are some easy-to-remember properties of factorials:
- \( 0! = 1 \), which is a special convention in mathematics.
- Factorials grow very rapidly as \( n \) increases.
Binomial Coefficient
The binomial coefficient is a central concept in combinatorial mathematics and is represented as \( _{n}C_{r} \). It indicates the number of ways to choose \( r \) items from \( n \) items without considering the order. The formula to calculate the binomial coefficient is: \[ _{n}C_{r} = \frac{n!}{r!(n-r)!} \] This formula reveals how many combinations can be made from a larger set \( n \) by selecting \( r \) elements. It's important in probability, statistics, and various fields of mathematics and science. Let's break down this formula:
- \( n! \) (n factorial) accounts for the total number of ways to arrange \( n \) items.
- \( r! \) is used to account for the arrangement of the \( r \) selected items.
- \( (n-r)! \) accounts for the remaining items not chosen.
Combinatorial Mathematics
Combinatorial mathematics deals with the study of counting, arrangement, and combination of elements within a set. It plays a critical role in solving problems related to counting and arrangements where order may or may not matter. Employing combinatorial principles, we can solve complex real-world problems, as seen with combinations and permutations. The primary focus in combinatorial mathematics is to find creative ways to arrange or select items from a set under given constraints. This can involve dealing with repeated elements, different constraints, or varying types of objects. Some key aspects of combinatorial mathematics include:
- Combinations: Focuses on picking items from a set without worrying about the order. This is the concept behind \( _{n}C_{r} \).
- Permutations: Deals with arranging all members of a set in order, where the order does matter.
- Algorithms: Combinatorial mathematics often involves developing algorithms for computing these arrangements efficiently.