Chapter 4: Problem 24
Movie Selections The Foreign Language Club is showing a four-movie marathon of subtitled movies. How many ways can they choose 4 from the 11 available?
Short Answer
Expert verified
There are 330 ways to choose 4 movies from 11 available movies.
Step by step solution
01
Understanding the Problem
We are tasked with selecting 4 movies from a total of 11 available movies for a marathon. This selection process does not consider the order of selection, meaning it is a combination problem.
02
Using the Combination Formula
The number of ways to choose 4 movies from 11 is given by the combination formula: \[ C(n, r) = \frac{n!}{r!(n-r)!} \]where \( n \) is the total number of movies (11) and \( r \) is the number of movies to choose (4).
03
Substituting Values
Substitute 11 for \( n \) and 4 for \( r \) in the combination formula: \[ C(11, 4) = \frac{11!}{4!(11-4)!} = \frac{11!}{4! \times 7!} \]
04
Calculating Factorials
Calculate the factorials:- \( 11! = 11 \times 10 \times 9 \times 8 \times 7! \) (We can ignore the rest of the terms since \( 7! \) will cancel out)- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
05
Simplifying the Expression
Substitute back into the expression:\[ C(11, 4) = \frac{11 \times 10 \times 9 \times 8 \times 7!}{4! \times 7!} \]The \( 7! \) terms cancel out, leaving:\[ C(11, 4) = \frac{11 \times 10 \times 9 \times 8}{24} \]
06
Solving the Expression
Perform the multiplication in the numerator:- \( 11 \times 10 = 110 \)- \( 110 \times 9 = 990 \)- \( 990 \times 8 = 7920 \)Now, divide by the denominator:\[ C(11, 4) = \frac{7920}{24} = 330 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Factorials
A fundamental concept in combinatorics is the use of factorials, often symbolized by the exclamation mark \( ! \). Understanding factorials is crucial when dealing with permutations and combinations. A factorial of a non-negative integer \( n \) is the product of all positive integers less than or equal to \( n \). It is denoted as \( n! \). For example:
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 0! = 1 \) by definition, which is essential for simplifying equations
Using the Combination Formula
The combination formula is a tool for calculating the number of ways to choose items without regard to order, from a larger set. This is crucial in many mathematics problems, particularly those involving selection or arrangement.The formula is expressed as:\[ C(n, r) = \frac{n!}{r!(n-r)!} \]Here, \( n \) is the total number of items to choose from, and \( r \) is the number of items to be chosen. In essence:
- \( n! \) counts all possible arrangements of the entire set of items.
- \( r! \) accounts for the arrangements of the items chosen.
- \( (n-r)! \) handles the arrangements of the items not chosen.
Problem-Solving in Mathematics
Problem-solving in mathematics often involves understanding the core principles behind the formulas and applying them to real-world scenarios. With problems involving combinations, identify scenarios where order does not matter.Consider these steps when solving such problems:
- **Identify the Total and the Selection:** Determine \( n \) and \( r \) for your problem. In the movie example, \( n = 11 \) and \( r = 4 \).
- **Use the Correct Formula:** Apply the combination formula, given that order doesn't matter.
- **Simplify the Calculation:** Use properties like the cancellation of similar factorials to ease computing large numbers.
- **Calculate Carefully:** Ensure correct multiplication and division to avoid errors in your final answer.