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The mean of a distribution is 20 and the standard deviation is 2. Use Chebyshev’s theorem. a. At least what percentage of the values will fall between 10 and 30? b. At least what percentage of the values will fall between 12 and 28?

Short Answer

Expert verified
a. At least 96% of the values fall between 10 and 30. b. At least 93.75% of the values fall between 12 and 28.

Step by step solution

01

Understanding Chebyshev's Theorem

Chebyshev's theorem states that for any data set, at least \(1 - \frac{1}{k^2}\) of the data values fall within \(k\) standard deviations of the mean, where \(k > 1\). This theorem applies to any distribution regardless of its shape.
02

Calculating k for Range 10 to 30

The mean of the distribution is 20. The range 10 to 30 represents a span from the mean to 10 units above and below it. Since the standard deviation is 2, we calculate \(k\) as follows: \(k = \frac{30 - 20}{2} = 5\) and \(k = \frac{20 - 10}{2} = 5\). Therefore, \(k = 5\) in both cases.
03

Applying Chebyshev's Theorem for Range 10 to 30

Using \(k = 5\) in Chebyshev's theorem, at least \(1 - \frac{1}{5^2}\) of the data values fall within 5 standard deviations of the mean. This gives us at least \(1 - \frac{1}{25} = 1 - 0.04 = 0.96\) or 96% of the data values between 10 and 30.
04

Calculating k for Range 12 to 28

For the range 12 to 28, we calculate \(k\) for one side of the mean: \(k = \frac{28 - 20}{2} = 4\) and \(k = \frac{20 - 12}{2} = 4\). So, \(k = 4\) in both cases.
05

Applying Chebyshev's Theorem for Range 12 to 28

Using \(k = 4\) in Chebyshev's theorem, at least \(1 - \frac{1}{4^2}\) of the data values fall within 4 standard deviations of the mean. This results in at least \(1 - \frac{1}{16} = 1 - 0.0625 = 0.9375\) or 93.75% of the data values between 12 and 28.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mean and standard deviation
Understanding the concepts of mean and standard deviation is fundamental in statistics. The mean, often referred to as the average, is the central value around which data points in a distribution tend to cluster. Think of it as the balance point in a data set. It is calculated by adding up all the values and dividing by the number of data points. In our exercise, the mean is given as 20, meaning most of the values in this distribution are centered around 20.

The standard deviation quantifies the amount of variation or dispersion in a set of data values. A smaller standard deviation indicates that the data points tend to be close to the mean, whereas a larger standard deviation suggests that the data is spread out over a broader range of values. In our example, the standard deviation is 2, conveying that on average, data points deviate by 2 units from the mean.

These values are crucial when applying Chebyshev's theorem, as they help determine how data is distributed around the mean. Understanding these concepts allows us to grasp what's typical in a distribution and measure the spread of data points around the central tendency.
data distribution
Data distribution is a concept that describes how data points are spread or distributed across different values in a data set. It provides insight into the shape, spread, and center of the data. Various types of distributions exist, including normal, skewed, binomial, and more. However, not all distributions follow a normal bell-shaped curve. This is where Chebyshev’s theorem becomes particularly handy.

Chebyshev’s theorem offers a way to understand data distribution without specific distribution assumptions. It states that for any data set, regardless of the distribution's shape, a specified percentage of values lie within a certain number of standard deviations from the mean. For example, using this theorem, at least 96% of the data in our exercise lies between 10 and 30 due to the calculated standard deviations.

This principle helps in understanding how spread out the data is and allows statisticians and researchers to draw conclusions about the proximity of data points to the mean. It becomes especially useful when data doesn’t satisfy the properties of common distributions like the normal distribution.
statistical range calculation
Statistical range calculation refers to the process of determining the spread of data in a given set by finding the difference between the maximum and minimum values. It's a simple measure of variability, which indicates the extent of dispersion in a data set.

However, in more complex situations, like those requiring Chebyshev's theorem, we delve into calculating how actual percentages of data fall within a specific range using the concept of standard deviations. This involves calculating the value of \(k\), which represents how many standard deviations a particular range encompasses around the mean.

For example, in our exercise, the range from 10 to 30 and from 12 to 28 around the mean (which is 20) determine the \(k\) values needed. With a standard deviation of 2, the calculations show that ranges encompass either 5 or 4 standard deviations on each side of the mean. By applying Chebyshev’s theorem with these \(k\) values, we can precisely state the minimum percentage of data within these intervals. This precise calculation gives us crucial insights into the concentration of data points and how they are distributed within a specified range.

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Most popular questions from this chapter

The frequency distribution shows a sample of the waterfall heights, in feet, of 28 waterfalls. Find the variance and standard deviation for the data. \(\begin{array}{ccc}{\text { Class boundaries }} & {\text { Frequency }} \\\ \hline 52.5-185.5 & {8} \\ {185.5-318.5} & {} {8} \\ {318.5-451.5} & {} {11} \\\ {318.5-451.5} & {2} \\ {451.5-584.5} & {1} \\ {584.5-717.5} & {4} \\\ {717.5-850.5} & {2}\end{array}\)

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The mean of the waiting times in an emergency room is 80.2 minutes with a standard deviation of 10.5 minutes for people who are admitted for additional treatment. The mean waiting time for patients who are discharged after receiving treatment is 120.6 minutes with a standard deviation of 18.3 minutes. Which times are more variable?

The increases (in cents) in cigarette taxes for 17 states in a 6-month period are 60, 20, 40, 40, 45, 12, 34, 51, 30, 70, 42, 31, 69, 32, 8, 18, 50 Find the range, variance, and standard deviation for the data. Use the range rule of thumb to estimate the standard deviation. Compare the estimate to the actual standard deviation.

The number of foreign workers’ certificates for the New England states and the northwestern states is shown. Find the mean, median, and mode for both areas and compare the results. New England states \(\quad\)Northwestern states \(\begin{array}{ccc}{6768} & {1870} \\ {3196} & {622} \\ {1112} & {620} \\\ {819} & {23} \\ {1019} & {172} \\ {1795} & {112}\end{array}\)

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