Chapter 3: Problem 3
What is the difference between a percentage and a percentile?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 3: Problem 3
What is the difference between a percentage and a percentile?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
If the mean of five values is 64, find the sum of the values.
A recent survey of a new diet cola reported the following percentages of people who liked the taste. Find the weighted mean of the percentages. \(\begin{array}{ccc}{\text { Area }} & {\% \text { Favored }} & {\text { Number surveyed }} \\ \hline 1 & {40} & {1000} \\ {2} & {30} & {3000} \\ {3} & {50} & {800}\end{array}\)
A measure to determine the skewness of a distribution is called the Pearson coefficient (PC) of skewness. The formula is $$\mathrm{PC}=\frac{3(\bar{X}-\mathrm{MD})}{s}$$ The values of the coefficient usually range from \(-3\) to \(+3 .\) When the distribution is symmetric, the coefficient is zero; when the distribution is positively skewed, it is positive; and when the distribution is negatively skewed, it is negative. Using the formula, find the coefficient of skewness for each distribution, and describe the shape of the distribution. a. Mean = 10, median = 8, standard deviation = 3. b. Mean = 42, median = 45, standard deviation = 4. c. Mean = 18.6, median = 18.6, standard deviation = 1.5. d. Mean = 98, median = 97.6, standard deviation = 4.
For this data set, find the mean and standard deviation of the variable. The data represent the ages of 30 customers who ordered a product advertised on television. Count the number of data values that fall within 2 standard deviations of the mean. Compare this with the number obtained from Chebyshev’s theorem. Comment on the answer. \(\begin{array}{lllll}{42} & {44} & {62} & {35} & {20} \\ {30} & {56} & {20} & {23} & {41} \\ {55} & {22} & {31} & {27} & {66} \\ {21} & {18} & {24} & {42} & {25} \\ {32} & {50} & {31} & {26} & {36} \\ {39} & {40} & {18} & {36} & {22}\end{array}\)
The frequency distribution shows a sample of the waterfall heights, in feet, of 28 waterfalls. Find the variance and standard deviation for the data. \(\begin{array}{ccc}{\text { Class boundaries }} & {\text { Frequency }} \\\ \hline 52.5-185.5 & {8} \\ {185.5-318.5} & {} {8} \\ {318.5-451.5} & {} {11} \\\ {318.5-451.5} & {2} \\ {451.5-584.5} & {1} \\ {584.5-717.5} & {4} \\\ {717.5-850.5} & {2}\end{array}\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.