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In a study of reaction times to a specific stimulus, a psychologist recorded these data (in seconds). Find the variance and standard deviation for the data. \(\begin{array}{lc}{\text { Class limits }} & {\text { Frequency }} \\ \hline 2.1-2.7 & {12} \\ {2.8-3.4} & {13} \\ {3.5-4.1} & {7} \\ {4.2-4.8} & {5} \\\ {4.9-5.5} & {2} \\ {5.6-6.2} & {1}\end{array}\)

Short Answer

Expert verified
Variance is approximately 0.61, and standard deviation is approximately 0.78 seconds.

Step by step solution

01

Calculate Midpoints

The midpoint of each class interval is calculated by averaging the upper and lower boundaries. For example, for the class 2.1-2.7, the midpoint is \((2.1 + 2.7) / 2 = 2.4\). Repeat this for each class.
02

Find the Weighted Mean

Use the formula \( \overline{x} = \frac{\sum{(f \,\cdot\, x_m)}}{\sum{f}} \), where \(f\) is the frequency and \(x_m\) is the midpoint. Calculate \(f \,\cdot\, x_m\) for each class and sum them to find \(\sum{(f \,\cdot\, x_m)}\). Then divide by the total frequency, \(\sum{f}\), to get the mean.
03

Calculate Deviations Squared

For each class, calculate \((x_m - \overline{x})^2\), where \(x_m\) is the midpoint and \(\overline{x}\) is the mean found in Step 2.
04

Find the Weighted Variance

Use the formula \( \sigma^2 = \frac{\sum{(f \,\cdot\, (x_m - \overline{x})^2)}}{\sum{f}} \). Multiply each squared deviation by its frequency, sum these products, and divide by the total frequency to find the variance.
05

Calculate the Standard Deviation

The standard deviation \(\sigma\) is the square root of the variance \(\sigma^2\). Calculate it to complete the analysis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variance Calculation
Variance is a critical concept in statistics representing how much each number in a dataset deviates from the mean.
It helps us understand the spread of data points around the average. To calculate variance, follow these steps:
  • Start by determining the midpoint for each class interval. This is already done by averaging the lower and upper boundaries of each class.
  • Next, compute the mean (\(\overline{x}\)) using the formula: \[\overline{x} = \frac{\sum{(f \,\cdot\, x_m)}}{\sum{f}}\]Where \(f\) is the frequency and \(x_m\) is the midpoint of each class.
  • Then, calculate the squared deviation for each midpoint: \((x_m - \overline{x})^2\).
  • Finally, find the weighted variance: \(\sigma^2 = \frac{\sum{(f \,\cdot\, (x_m - \overline{x})^2)}}{\sum{f}}\), by summing up all weighted squared deviations and dividing by the total frequency.
    This result tells us how data points are dispersed around the mean in the distribution.
Standard Deviation
Standard deviation is essentially the root of variance. It provides a measure of the average distance of each data point from the mean.
It is a widely used indicator of data variability.Here's how you can compute it:- After you have calculated the variance (\(\sigma^2\)), simply take the square root of that value to find the standard deviation (\(\sigma\)). - The formula is: \[\sigma = \sqrt{\sigma^2}\]Standard deviation offers an intuitive grasp of variability.
Data clustered closely around the mean will yield a smaller standard deviation, while a greater spread results in a larger value.
This metric is crucial in fields like psychology to understand reaction time variability and overall consistency.
Frequency Distribution
A frequency distribution is a structured way to present data. It showcases data values and their corresponding frequencies.
Frequencies tell you how often a particular data point or range appears. The exercise provided involves a frequency distribution table with class intervals and their frequencies. - Each class, like 2.1-2.7, shows a range of data values. - The frequency number beside it (e.g., 12) indicates how many data points fall within that range. This setup helps visualize the distribution of reaction times in the psychological study.
Frequency distributions allow easy identification of trends, such as which time ranges are more common. They are fundamental in statistical analysis for summarizing large collections of data, making patterns and variations clearer.
Midpoint Calculation
Midpoint calculation simplifies the summarization of interval data.
Midpoints act as representatives for each class interval and are crucial in finding central tendency measures.To calculate midpoints:- For each interval, add the lower and upper bounds, then divide the sum by 2.
For example, for the interval 2.1-2.7, the midpoint is calculated as \((2.1 + 2.7) / 2 = 2.4\).- Repeat this process for every class in your frequency distribution table.Midpoints provide approximations for the varying values within an interval.
This method assumes values in the class are evenly distributed, providing a balance point for data in that range.
They're vital for subsequent statistical calculations, such as mean and variance, helping combine class characteristics into a single figure.

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Most popular questions from this chapter

The hourly compensation costs (in U.S. dollars) for production workers in selected countries are represented below. Find the mean and modal class for the data. Class\(\quad\) Frequency \(\begin{aligned} 2.48-7.48 & & & 7 \\ 7.49-12.49 & & 3 \\ 12.50-17.50 & & 1 \\\ 17.51-22.51 & & 7 \\ 22.52-27.52 & & 5 \\ 27.53-32.53 & & 5 \end{aligned}\)

The number of annual precipitation days for one-half of the 50 largest U.S. cities is listed below. Find the range, variance, and standard deviation of the data. \(\begin{array}{llllllllll}{135} & {128} & {136} & {78} & {116} & {77} & {111} & {79} & {44} & {97} \\ {116} & {123} & {88} & {102} & {26} & {82} & {156} & {133} & {107} & {35} \\ {112} & {98} & {45} & {122} & {125} & {}\end{array}\)

The mean and standard deviation of the number of hours the employees work in the music store per week are, respectively, 18.6 and 3.2 hours. If the owner increases the number of hours each employee works per week by 4 hours, what will be the new mean and standard deviation of the number of hours worked by the employees?

The average number of calories in a regular-size bagel is 240. If the standard deviation is 38 calories, find the range in which at least 75% of the data will lie. Use Chebyshev’s theorem.

The harmonic mean (HM) is defined as the number of values divided by the sum of the reciprocals of each value. The formula is $$\mathrm{HM}=\frac{n}{\Sigma(1 / X)}$$ For example, the harmonic mean of \(1,4,5,\) and 2 is $$\mathrm{HM}=\frac{4}{1 / 1+1 / 4+1 / 5+1 / 2} \approx 2.051$$ This mean is useful for finding the average speed. Suppose a person drove 100 miles at 40 miles per hour and returned driving 50 miles per hour. The average miles per hour is not 45 miles per hour, which is found by adding 40 and 50 and dividing by 2. The average is found as shown. Since $$\text { Time }=\text { distance } \div \text { rate }$$ then $$\begin{array}{l}{\text { Time } 1=\frac{100}{40}=2.5 \text { hours to make the trip }} \\ {\text { Time } 2=\frac{100}{50}=2 \text { hours to return }}\end{array}$$ Hence, the total time is 4.5 hours, and the total miles driven are \(200 .\) Now, the average speed is $$\text { Rate }=\frac{\text { distance }}{\text { time }}=\frac{200}{4.5} \approx 44.444 \text { miles per hour }$$ This value can also be found by using the harmonic mean formula $$\mathrm{HM}=\frac{2}{1 / 40+1 / 50} \approx 44.444$$ Using the harmonic mean, find each of these. a. A salesperson drives 300 miles round trip at 30 miles per hour going to Chicago and 45 miles per hour returning home. Find the average miles per hour. b. A bus driver drives the 50 miles to West Chester at 40 miles per hour and returns driving 25 miles per hour. Find the average miles per hour. c. A carpenter buys \(\$ 500\) worth of nails at \(\$ 50\) per pound and \(\$ 500\) worth of nails at \(\$ 10\) per pound. Find the average cost of 1 pound of nails.

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