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Assume that the variables are normally or approximately normally distributed. Use the traditional method of hypothesis testing unless otherwise specified. A nutritionist claims that the standard deviation of the number of calories in 1 tablespoon of the major brands of pancake syrup is \(60 .\) A random sample of major brands of syrup is selected, and the number of calories is shown. At \(\alpha=0.10,\) can the claim be rejected? \(\begin{array}{rrrrrr}53 & 210 & 100 & 200 & 100 & 220 \\ 210 & 100 & 240 & 200 & 100 & 210 \\ 100 & 210 & 100 & 210 & 100 & 60\end{array}\)

Short Answer

Expert verified
Reject the null hypothesis if the test statistic falls outside the critical chi-square range.

Step by step solution

01

State the Hypotheses

We need to test the claim about the standard deviation. The null hypothesis \( H_0 \) is that the standard deviation of the calories is \( \sigma = 60 \). The alternative hypothesis \( H_1 \) is \( \sigma eq 60 \).
02

Calculate the Sample Standard Deviation

First, find the mean of the sample data. Then use the formula for the sample standard deviation:\[ s = \sqrt{\frac{1}{n-1} \sum_{i=1}^{n}(x_i-\bar{x})^2} \]Calculate the mean and then the standard deviation using the given data entries.
03

Compute the Test Statistic

Use the chi-square test statistic for the standard deviation:\[ \chi^2 = \frac{(n-1) \cdot s^2}{\sigma^2} \]Here, \( n \) is the number of samples, \( s \) is the sample standard deviation, and \( \sigma = 60 \) is the claimed standard deviation.
04

Find the Critical Values

Since we have alternative hypothesis \( \sigma eq 60 \), it's a two-tailed test. Use the chi-square distribution table with \( \alpha = 0.10 \) and \( n-1 \) degrees of freedom to find the critical chi-square values.
05

Make the Decision

Compare the test statistic with the critical values determined in Step 4. If the test statistic falls outside the range determined by the critical values, reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Standard Deviation
Standard deviation is an important concept in statistics that measures the amount of variation or dispersion in a set of values. It tells us how close or spread out the data points are around the mean.
For example, in the given problem, the nutritionist claims that the standard deviation of calories is 60. Essentially, this means most data points are expected to be within 60 calories of the mean.
  • A low standard deviation suggests that the data points are close to the mean.
  • A high standard deviation indicates that the data points are spread out over a larger range of values.
When calculating the sample standard deviation, we use the formula: \[ s = \sqrt{\frac{1}{n-1} \sum_{i=1}^{n}(x_i-\bar{x})^2} \]Here, \( n \) is the number of observations, \( x_i \) is each individual observation, and \( \bar{x} \) is the mean of the observations. This formula helps us determine the variability in the sample data.
Chi-Square Test for Standard Deviation
The chi-square test is a statistical method that examines if a sample variance (or standard deviation) differs significantly from a specific value. It's particularly useful in hypothesis testing, especially for variances.
In this scenario, the problem involves testing whether the standard deviation of calories in pancake syrup is 60. To perform this test, calculate the test statistic using:
  • \( \chi^2 = \frac{(n-1) \cdot s^2}{\sigma^2} \)
Here, \( \chi^2 \) represents the chi-square test statistic, \( n \) is the sample size, \( s \) is the sample standard deviation, and \( \sigma \) is the claimed standard deviation.
You’ll compare this test statistic to critical values from the chi-square distribution table, which depend on the chosen significance level \( \alpha \) and degrees of freedom \( (n-1) \). The outcome helps decide whether to reject or not reject the null hypothesis, \( H_0 \), that the standard deviation is indeed 60.
Normal Distribution and Its Importance
The normal distribution, often referred to as the bell curve, is vital in statistics because it describes how values are spread in many real-life phenomena.
When data is normally distributed, it is symmetrically centered around a mean with an equal proportion of values on both sides.
  • Most values lie close to the mean.
  • It forms a shape that’s highest at the mean and tapers off equally on both sides.
In hypothesis testing, especially when working with standard deviation and chi-square tests, assuming that data is normally distributed allows the appropriate application of these statistical tests.
For instance, in the given exercise, we assume the calorie counts are normally distributed, allowing the use of the chi-square test to determine if the sample standard deviation significantly deviates from the claimed value of 60. This assumption is crucial as it validates the use of techniques that help in decision-making processes based on sample data.

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Most popular questions from this chapter

What is meant by a statistical test?

Perform each of the following steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Find the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume that the population is approximately normally distributed. The U.S. Bureau of Labor and Statistics reported that a person between the ages of 18 and 34 has had an average of 9.2 jobs. To see if this average is correct, a researcher selected a random sample of 8 workers between the ages of 18 and 34 and asked how many different places they had worked. The results were as follows: $$ \begin{array}{llllllll} 8 & 12 & 15 & 6 & 1 & 9 & 13 & 2 \end{array} $$ At \(\alpha=0.05,\) can it be concluded that the mean is \(9.2 ?\) Use the \(P\) -value method. Give one reason why the respondents might not have given the exact number of jobs that they have worked.

Perform each of the following steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Researchers suspect that \(18 \%\) of all high school students smoke at least one pack of cigarettes a day. At Wilson High School, a randomly selected sample of 300 students found that 50 students smoked at least one pack of cigarettes a day. At \(\alpha=0.05,\) test the claim that less than \(18 \%\) of all high school students smoke at least one pack of cigarettes a day. Use the \(P\) -value method.

A researcher claims that the yearly consumption of soft drinks per person is 52 gallons. In a sample of 50 randomly selected people, the mean of the yearly consumption was 56.3 gallons. The standard deviation of the population is 3.5 gallons. Find the \(P\) -value for the test. On the basis of the \(P\) -value, is the researcher's claim valid?

What is meant by the critical region? The noncritical region?

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