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Assume all variables are binomial. (Note: If values are not found in Table B of Appendix \(A,\) use the binomial formula. High Blood Pressure Twenty percent of Americans ages 25 to 74 have high blood pressure. If 16 randomly selected Americans ages 25 to 74 are selected, find each probability. a. None will have high blood pressure. b. One-half will have high blood pressure. c. Exactly 4 will have high blood pressure.

Short Answer

Expert verified
a. \(\approx 0.028\), b. \(\approx 0.0003\), c. \(\approx 0.218\).

Step by step solution

01

Understand the Problem

We are dealing with a binomial distribution problem where the probability of success (having high blood pressure) is given as 0.20 or 20%. The sample size is 16. We need to find the probabilities for different scenarios where a certain number of people have high blood pressure.
02

Identify the Binomial Parameters

The number of trials \( n = 16 \) and the probability of success \( p = 0.20 \). The probability of failure \( q = 1 - p = 0.80 \).
03

Probability Formula for Binomial Distribution

The probability of getting exactly \( k \) successes in \( n \) trials is given by the formula \( P(X=k) = \binom{n}{k} p^k q^{n-k} \).
04

Calculate Probability for None Having High Blood Pressure

Substitute \( k = 0 \) into the formula. \[ P(X=0) = \binom{16}{0} (0.20)^0 (0.80)^{16} = 1 \times 1 \times 0.80^{16} \] Calculate \( 0.80^{16} \).
05

Evaluate Result for a

Calculating this gives \( 0.80^{16} \approx 0.028 \). Therefore, the probability that none have high blood pressure is approximately 0.028.
06

Calculate Probability for One-Half Having High Blood Pressure

One-half of 16 is 8, so we need the probability that exactly 8 have high blood pressure: \[ P(X=8) = \binom{16}{8} (0.20)^8 (0.80)^8 \].
07

Evaluate the Binomial Coefficient

Calculate \( \binom{16}{8} = 12870 \).
08

Calculate the Probability for Half Having High Blood Pressure

Evaluate: \[ P(X=8) = 12870 \times (0.20)^8 \times (0.80)^8 \].Simplifying gives a probability of nearly 0.0003.
09

Calculate Probability for Exactly 4 Having High Blood Pressure

Substitute \( k = 4 \) into the formula to find \( P(X=4) = \binom{16}{4} (0.20)^4 (0.80)^{12} \).
10

Evaluate Result for c

Calculate \( \binom{16}{4} = 1820 \). Then calculate \( 1820 \times (0.20)^4 \times (0.80)^{12} \), which equals approximately 0.218.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Formula
The probability formula for a binomial distribution is an essential tool for understanding how likely a specific outcome is. In a binomial distribution, we focus on the probability of a certain number of successes happening in a series of independent trials. The trials must be identical and must satisfy two conditions: each trial can only result in a success or a failure, and the probability of success remains constant across trials.

The formula used to calculate the probability of getting exactly \( k \) successes in \( n \) trials is:
  • \( P(X=k) = \binom{n}{k} p^k q^{n-k} \)
Here:
  • \( \binom{n}{k} \) is the binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \)
  • \( p \) is the probability of success on one trial
  • \( q \) is the probability of failure on one trial, calculated as \( q = 1 - p \)
This formula helps in evaluating exact probabilities for various cases within a binomial framework.
Binomial Parameters
In any problem involving a binomial distribution, it is crucial to correctly identify the parameters of the binomial distribution. These parameters help to define the structure of the problem and set the stage for calculations.
  • The number of trials, denoted by \( n \), is the total number of times the experiment is conducted. In some questions, this could refer to the number of people surveyed, the number of times an event happens, etc. In our case, \( n = 16 \), since we are looking at 16 randomly selected individuals.
  • The probability of success, denoted by \( p \), is the chance of one trial resulting in a success. It's crucial to know what success means in your context. Here, success means having high blood pressure, with a probability \( p = 0.20 \).
  • The probability of failure, denoted by \( q \), is the chance of one trial failing. This is calculated as \( q = 1 - p \), which means \( q = 0.80 \) in this scenario.
These parameters are foundational and are always needed to utilize the probability formula successfully.
Binomial Coefficient
The binomial coefficient is a crucial component of the binomial probability formula. It indicates the number of ways to choose \( k \) successes from \( n \) trials without considering the order of successes.

The binomial coefficient is represented as \( \binom{n}{k} \) and can be computed using the formula:
  • \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
Where \( n! \) (n factorial) is the product of all positive integers up to \( n \).

Example:

For instance, if we want to calculate \( \binom{16}{8} \), it tells us the number of ways to select 8 people out of 16 to have high blood pressure. Using the factorial method:
  • \( \binom{16}{8} = \frac{16!}{8! \, 8!} = 12870 \). This value shows how many combinations are possible for this configuration.
Understanding and calculating the binomial coefficient correctly is critical as it directly impacts the probability results.
Calculating Probabilities
Calculating probabilities in a binomial distribution involves putting it all together: using the formula, parameters, and coefficients. You determine probabilities for various scenarios by substituting into the binomial probability formula.

Let's walk through two examples:

  • Example 1: None have high blood pressure
    Substitute \( k = 0 \). Using the formula: \[ P(X=0) = \binom{16}{0} (0.20)^0 (0.80)^{16} \] \( \binom{16}{0} = 1 \), so the probability becomes \( 1 \times 1 \times 0.80^{16} \), approximately 0.028.
  • Example 2: Exactly 4 have high blood pressure
    Substitute \( k = 4 \). Using the formula: \[ P(X=4) = \binom{16}{4} (0.20)^4 (0.80)^{12} \] \( \binom{16}{4} = 1820 \), so calculate \( 1820 \times (0.20)^4 \times (0.80)^{12} \) to get about 0.218.
By employing the formula consistently with the correct parameters, you can effectively determine and understand the likelihood of different outcomes occurring in a practical and reliable way.

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Most popular questions from this chapter

Assume all variables are binomial. (Note: If values are not found in Table B of Appendix \(A,\) use the binomial formula. In 2014 the percentage of the U.S. population that speak English only in the home is \(78.9 \%\). Choose 15 U.S. people at random. What is the probability that exactly one-third of them speak English only? At least one-third? What is the probability that at least 9 do not speak English in the home?

If a person rolls doubles when she tosses two dice, she wins \(\$ 5 .\) For the game to be fair, how much should she pay to play the game?

In 2014 the percentage of the U.S. population who was foreign-born was 13.1. Choose 60 U.S. residents at random. How many would you expect to be American- born? Find the mean, variance, and standard deviation for the number who are foreign-born.

Construct a probability distribution for the data and draw a graph for the distribution. Mathematics Tutoring Center At a drop-in mathematics tutoring center, each teacher sees 4 to 8 students per hour. The probability that a tutor sees 4 students in an hour is \(0.117 ; 5\) students, 0.123 6 students, 0.295 ; and 7 students, 0.328 . Find the probability that a tutor sees 8 students in an hour, construct the probability distribution, and draw the graph.

The leading digits in actual data, such as stock prices, population numbers, death rates, and lengths of rivers, do not occur randomly as one might suppose, but instead follow a distribution according to Benford's law. Below is the probability distribution for the leading digits in real-life lists of data. Calculate the mean for the distribution.$$ \begin{array}{l|llllllll} \boldsymbol{X} & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\ \hline \boldsymbol{P}(\boldsymbol{X}) & 0.301 & 0.176 & 0.125 & 0.097 & 0.079 & 0.067 & 0.058 & 0.051 & 0.046 \end{array} $$

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