Chapter 4: Problem 62
How many different signals can be made by using at least 3 different flags if there are 5 different flags from which to select?
Short Answer
Expert verified
300 signals can be made using at least 3 different flags.
Step by step solution
01
Determine Total Flags
We have a total of 5 different flags to choose from: let's label them as A, B, C, D, and E.
02
Using Three Flags
First, we calculate the number of signals possible using exactly 3 different flags. The number of ways to choose 3 flags out of the 5 available flags is given by the binomial coefficient \( \binom{5}{3} \). This calculates to \( \binom{5}{3} = 10 \). Each selection of 3 flags can be arranged in \(3! = 6\) different ways. Thus, the total number of arrangements for 3 flags is \(10 \times 6 = 60\).
03
Using Four Flags
Next, calculate the number of signals possible using exactly 4 different flags. The number of ways to choose 4 flags out of the 5 available flags is given by \( \binom{5}{4} \). This calculates to \( \binom{5}{4} = 5 \). Each selection of 4 flags can be arranged in \(4! = 24\) different ways. Thus, the total number of arrangements for 4 flags is \(5 \times 24 = 120\).
04
Using Five Flags
Lastly, calculate the number of signals possible using all 5 different flags. Here, the number of ways to choose 5 flags from 5 is \( \binom{5}{5} = 1 \). These 5 flags can be arranged in \(5! = 120\) different ways.
05
Total Signals
Add together all the possible signals from steps 2, 3, and 4 to find the total number of signals that can be made using at least 3 flags. This is \(60 + 120 + 120 = 300\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficient
In combinatorics, the binomial coefficient is a fundamental tool used to determine the number of ways to choose a subset of items from a larger set when the order does not matter. The binomial coefficient is typically denoted as \( \binom{n}{k} \), where \( n \) is the total number of items, and \( k \) is the number of items to choose. It can be computed using the formula: \[\binom{n}{k} = \frac{n!}{k!(n-k)!}\] This formula arises from the concept of permutations divided by the number of overlap permutations that occur. For instance, in the given exercise, we calculated \( \binom{5}{3} \), meaning we choose 3 flags out of 5, which results in 10 different combinations, regardless of order.
- It helps identify subsets.
- Used in probability and statistics.
- Determines paths in decision trees.
Permutation
A permutation is a specific arrangement or sequence of items, where the order does matter. When we talk about permutations, we are focusing on the various possible ways to order a set of items. In the exercise discussed, after selecting a subset of flags, we computed permutations to find how many different signals (or sequences) those flags can create. For example, the permutations of selecting 3 flags is calculated as \(3!\), which equals 6, indicating that each selection of 3 flags can be arranged in 6 different orders. The formula for permutations is: \[nPr = \frac{n!}{(n-r)!}\]
- A permutation values arrangement order.
- Highlights the importance of sequence in arrangements.
- Used in scheduling and organizing tasks.
Factorial
Factorials play a significant role in both permutations and combinations, making them indispensable in combinatorial mathematics. The factorial of a number \( n \) is denoted as \( n! \), which means you multiply \( n \) by every positive whole number below it until you reach 1. For example, \( 3! = 3 \times 2 \times 1 = 6 \). Factorials are used in the formulas for both permutations and combinations. In the provided exercise:
- The factorial is used to calculate permutations \( n! \).
- Provides solutions to combination as part of \( \binom{n}{k} \) formula \( \frac{n!}{k!(n-k)!} \).
- Determines possible arrangements in order-sensitive scenarios.