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91Ó°ÊÓ

For this data set, find the mean and standard deviation of the variable. The data represent the ages of 30 customers who ordered a product advertised on television. Count the number of data values that fall within 2 standard deviations of the mean. Compare this with the number obtained from Chebyshev's theorem. Comment on the answer. \(\begin{array}{lllll}42 & 44 & 62 & 35 & 20 \\ 30 & 56 & 20 & 23 & 41 \\ 55 & 22 & 31 & 27 & 66 \\ 21 & 18 & 24 & 42 & 25 \\ 32 & 50 & 31 & 26 & 36 \\\ 39 & 40 & 18 & 36 & 22\end{array}\)

Short Answer

Expert verified
Mean is 34.9, standard deviation is 14.98, with 29 data values within 2 standard deviations of the mean. Chebyshev's theorem predicts at least 23.

Step by step solution

01

Calculate the Mean

To find the mean of the data set, sum all the ages and divide by the number of data points. \[\text{Mean} = \frac{42 + 44 + 62 + 35 + 20 + 30 + 56 + 20 + 23 + 41 + 55 + 22 + 31 + 27 + 66 + 21 + 18 + 24 + 42 + 25 + 32 + 50 + 31 + 26 + 36 + 39 + 40 + 18 + 36 + 22}{30} = \frac{1047}{30} = 34.9\]
02

Calculate the Standard Deviation

First, find the variance by calculating the squared difference from the mean for each data point, summing these squares, and dividing by the number of observations minus 1 (N-1 = 29).\[\text{Variance} = \frac{\sum{(x_i - \text{Mean})^2}}{N-1} = \frac{(42-34.9)^2 + (44-34.9)^2 + ...}{29}\]The calculated variance is approximately 224.49. Taking the square root of the variance:\[\text{Standard Deviation} = \sqrt{224.49} \approx 14.98\]
03

Determine Data within 2 Standard Deviations

To find how many data points fall within 2 standard deviations of the mean, calculate the range defined by mean \(\pm\) 2 standard deviations.Calculate boundary values:\[\text{Lower Bound} = 34.9 - 2\times14.98 \approx 4.94\]\[\text{Upper Bound} = 34.9 + 2\times14.98 \approx 64.86\]Count the data points within this range. 29 data points fall within this range.
04

Apply Chebyshev's Theorem

Chebyshev's theorem states that at least \((1 - \frac{1}{k^2})\) of data values fall within \(k\) standard deviations from the mean, for \(k = 2\).\[1 - \frac{1}{2^2} = \frac{3}{4} = 0.75\]For 30 data points, at least 75% should fall within this range, which is 22.5 or approximately 23 data points. We found 29 points within this range.
05

Comment on the Comparison

Compare the actual count of data points within 2 standard deviations (29) to the minimum predicted by Chebyshev’s theorem (at least 23). In this case, significantly more data points fall within this range than Chebyshev’s theorem minimally predicts, indicating this distribution follows more of a normal distribution where data is often tightly clustered around the mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chebyshev's Theorem
Chebyshev's theorem is a powerful tool in statistics that provides a rule for all data distributions, regardless of their shape. This theorem states that for any dataset, the proportion of data points that fall within a certain number of standard deviations (\(k\)) from the mean is at least \(1 - \frac{1}{k^2}\). This characteristic means Chebyshev's theorem can be applied to any dataset without assuming a normal distribution. It's especially handy for non-normally distributed data.In the context of our exercise, we used \(k = 2\) as our number of standard deviations. The theorem tells us that at least 75% of our data points should be expected within this range. With 30 customer ages given, this means around 23 data points would fall within those 2 standard deviations from the mean. Notably, Chebyshev's theorem provides a conservative estimate, often predicting fewer observations than what might actually occur. In this exercise, we found that 29 data points were within this range, showing that Chebyshev's theorem often underestimates distribution clustering when it is closer to normal.
Normal Distribution
Normal distribution, often referred to as the bell curve, is a common pattern wherein data tends to be symmetrically distributed around the mean. In a perfect normal distribution:
  • About 68% of data falls within one standard deviation from the mean
  • About 95% within two standard deviations
  • About 99.7% within three standard deviations
Our exercise seems to showcase a trend that resembles a normal distribution, given that 29 out of 30 data points fall within two standard deviations of the mean. This is higher than the minimum suggested by Chebyshev's theorem and closer to what we might expect if the data were normally distributed. It's important to recognize when data might fit a normal distribution because it allows for the application of different statistical tests and inferences that are designed specifically for normal data. Further, a normal distribution often indicates a natural variability where values close to the average occur most frequently, tapering off as they move away from the mean.
Data Set Analysis
Performing a data set analysis involves several key steps, essential for understanding any given data collection. Here, we used customer ages to demonstrate a simple analysis: First, calculate the mean, which is 34.9. This represents the average age of the customers in our dataset. Then, the standard deviation was determined to be approximately 14.98. This number indicates how much the individual data points typically differ from the mean; a larger standard deviation suggests more variability in customer ages. Once we have these two crucial statistics, we can identify how the data is distributed around the mean. We checked the range that includes ages between 4.94 and 64.86 (twice the standard deviation from the mean) to count how many data points fall within this interval. By comparing this test case against Chebyshev’s estimation, and noticing the larger proportion within this range, we can infer that our dataset isn't just any typical distribution. Our data might hint at a pattern closer to a normal distribution. Analyzing datasets like these helps in developing informed conclusions, allowing businesses to understand groups better and make strategic decisions based on solid statistical findings.

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Most popular questions from this chapter

Of the 25 brightest stars, the distances from earth (in light-years) for those with distances less than 100 light-years are found below. Find the mean, median, mode, and midrange for the data. $$\begin{array}{lllllll}8.6 & 36.7 & 42.2 & 16.8 & 33.7 & 77.5 & 87.9 \\\4.4 & 25.3 & 11.4 & 65.1 & 25.1 & 51.5 &\end{array}$$

The costs of three models of helicopters are shown here. Find the weighted mean of the costs of the models. $$\begin{array}{lrr}\text { Model } & \text { Number sold } & \text { Cost } \\\\\hline \text { Sunscraper } & 9 & \$ 427,000 \\\\\text { Skycoaster } & 6 & 365,000 \\ \text { High-flyer } & 12 & 725,000\end{array}$$

The data show the heights in feet of 14 roller coasters. Find the mean, median, midrange, and mode for the data $$\begin{array}{rrrrrrr}95 & 105 & 50 & 125 & 102 & 120 & 160 \\\102 & 118 & 91 & 160 & 95 & 50 & 84\end{array}$$

The data for a recent year show the taxes (in millions of dollars) received from a random sample of 10 states. Find the first and third quartiles and the IQR. \(\begin{array}{llllllllll}13 & 15 & 32 & 36 & 11 & 24 & 6 & 25 & 11 & 71\end{array}\)

Harmonic Mean The harmonic mean (HM) is defined as the number of values divided by the sum of the reciprocals of each value. The formula is $$\mathrm{HM}=\frac{n}{\Sigma(1 / X)}$$ For example, the harmonic mean of \(1,4,5,\) and 2 is $$\mathrm{HM}=\frac{4}{1 / 1+1 / 4+1 / 5+1 / 2} \approx 2.051$$ This mean is useful for finding the average speed. Suppose a person drove 100 miles at 40 miles per hour and returned driving 50 miles per hour. The average miles per hour is not 45 miles per hour, which is found by adding 40 and 50 and dividing by 2 . The average is found as shown. Since Time \(=\) distance \(\div\) rate then Time \(1=\frac{100}{40}=2.5\) hours to make the trip Time \(2=\frac{100}{50}=2\) hours to return Hence, the total time is 4.5 hours, and the total miles driven are \(200 .\) Now, the average speed is $$\text { Rate }=\frac{\text { distance }}{\text { time }}=\frac{200}{4.5} \approx 44.444 \text { miles per hour }$$ This value can also be found by using the harmonic mean formula $$\mathrm{HM}=\frac{2}{1 / 40+1 / 50} \approx 44.444$$ Using the harmonic mean, find each of these. a. A salesperson drives 300 miles round trip at 30 miles per hour going to Chicago and 45 miles per hour returning home. Find the average miles per hour. b. A bus driver drives the 50 miles to West Chester at 40 miles per hour and returns driving 25 miles per hour. Find the average miles per hour. c. A carpenter buys \(\$ 500\) worth of nails at \(\$ 50\) per pound and \(\$ 500\) worth of nails at \(\$ 10\) per pound. Find the average cost of 1 pound of nails.

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