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In a two-way ANOVA, variable \(A\) has six levels and variable \(B\) has five levels. There are seven data values in each cell. Find each degrees-of-freedom value. a. d.f.N. for factor \(A\) b. d.f.N. for factor \(B\) c. d.f.N. for factor \(A \times B\) d. d.f.D. for the within (error) factor

Short Answer

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a. 5, b. 4, c. 20, d. 180

Step by step solution

01

Understand Degrees of Freedom for Factor A

The degrees of freedom for a factor is the number of levels of the factor minus one. For factor \(A\), since there are six levels, the degrees of freedom is calculated as \(6 - 1 = 5\).
02

Calculate Degrees of Freedom for Factor B

Just like factor \(A\), the degrees of freedom for factor \(B\) is the number of levels of the factor minus one. Since factor \(B\) has five levels, the degrees of freedom is \(5 - 1 = 4\).
03

Calculate Interaction Degrees of Freedom A × B

The interaction degrees of freedom for two factors is the product of the degrees of freedom for each individual factor. For \(A \times B\), it is \((6-1) \times (5-1) = 5 \times 4 = 20\).
04

Find Degrees of Freedom for Within (Error) Factor

The degrees of freedom for the within (error) factor is the total number of observations minus the number of groups for both factors. Total observations can be calculated as "levels of A \times levels of B \times participants in each cell = 6 \times 5 \times 7 = 210". The number of groups is \( (6 \times 5) = 30 \). Thus, \(210 - 30 = 180\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of freedom (d.f.) are a vital part of many statistical tests, including the two-way ANOVA. They can be thought of as the number of independent pieces of information you can use to estimate a parameter. In other words, degrees of freedom reflect how many values in your data can vary after certain constraints are applied.

In the context of a two-way ANOVA, the degrees of freedom for each factor is determined by the number of levels in that factor minus one. For instance, if factor \(A\) has six levels, the d.f. would be \(6 - 1 = 5\). This value represents the variability among the different levels of factor \(A\).

Similarly, the d.f. for factor \(B\) would be calculated in the same manner if it had five levels: \(5 - 1 = 4\). The concept of degrees of freedom is foundational in slicing up variance into parts that help assess the effects of the independent variables being studied.
Factor Levels
The term factor levels in an ANOVA refers to the different categories or groups within a factor in your experiment. If you're looking at a two-way ANOVA, you have two factors, each with its own set of levels.

For example, factor \(A\) could be different types of treatments, while factor \(B\) might be different time points at which a treatment is administered. The number of levels for factor \(A\) tells you how many different treatment groups there are; similarly, factor \(B\) informs you about the number of time points. In the exercise, factor \(A\) has six levels and factor \(B\) has five levels, indicating the richness and complexity of the data.

Understanding factor levels is crucial because they guide the calculation of the degrees of freedom and the structuring of the ANOVA table. The richness in levels enhances the analysis by allowing you to see how each level interacts with others.
Interaction Effect
The interaction effect in a two-way ANOVA tests whether the effect of one factor depends on the level of the other factor. It's about examining how different combinations of factor levels affect the dependent variable differently.

In practical terms, interaction effects reveal whether the influence of one factor changes across the levels of another factor. If an interaction is significant, it suggests that the interpretation of main effects needs to be considered in conjunction with this interaction.

To find the degrees of freedom for the interaction (\(A \times B\)) in a two-way ANOVA, you multiply the degrees of freedom for each factor: \( (6-1) \times (5-1) = 20 \). This number reflects the complexity added to your model by considering how factors work not just independently, but in combination.
Error Term
In the context of ANOVA, the error term refers to the variability within the data that is not explained by the factors. It's a measure of the variation within each factor level and is essential for determining the significance of the observed effects.

To calculate the degrees of freedom for the error term in a two-way ANOVA, you consider the total number of observations and subtract the number of groups formed by the factor levels. For the given problem, the total observations are \(6 \times 5 \times 7 = 210\) and the number of groups is \(6 \times 5 = 30\). Thus, the degrees of freedom for the error term is \(210 - 30 = 180\).

This error term is then used to assess the significance of observed factor effects through the F-statistic, helping to ensure that the conclusions drawn from the ANOVA are robust and reliable.

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Most popular questions from this chapter

Do a complete one-way ANOVA. If the null hypothesis is rejected, use either the Scheffé or Tukey test to see if there is a significant difference in the pairs of means. Assume all assumptions are met. The number of grams of fiber per serving for a random sample of three different kinds of foods is listed. Is there sufficient evidence at the 0.05 level of significance to conclude that there is a difference in mean fiber content among breakfast cereals, fruits, and vegetables? \(\begin{array}{ccc}\text { Breakfast cereals } & \text { Fruits } & \text { Vegetables } \\\\\hline 3 & 5.5 & 10 \\\4 & 2 & 1.5 \\\6 & 4.4 & 3.5 \\\4 & 1.6 & 2.7 \\\10 & 3.8 & 2.5 \\\5 & 4.5 & 6.5 \\\6 & 2.8 & 4 \\\8 & & 3 \\\5 & &\end{array}\)

A gardening company is testing new ways to improve plant growth. Twelve plants are randomly selected and exposed to a combination of two factors, a "Grow- light" in two different strengths and a plant food supplement with different mineral supplements. After a number of days, the plants are measured for growth, and the results (in inches) are put into the appropriate boxes. $$ \begin{array}{|c|c|} \hline \text { Grow-light } 1 & \text { Grow-light } 2 \\ \hline 9.2,9.4,8.9 & 8.5,9.2,8.9 \\ \hline 7.1,7.2,8.5 & 5.5,5.8,7.6 \\ \hline \end{array} $$ Can an interaction between the two factors be concluded? Is there a difference in mean growth with respect to light? With respect to plant food? Use \(\alpha=0.05 .\)

For Exercises 7 through 20 , assume that all variables are normally distributed, that the samples are independent, that the population variances are equal, and that the samples are simple random samples, one from each of the populations. Also, for each exercise, perform the following steps. The following data show the yearly budgets for leading business sectors in the United States. At \(\alpha=0.05\), is there a significant difference in the mean budgets of the business sectors? The data are in thousands of dollars. $$ \begin{array}{cccc} & \text { Food } & \text { Supportive } \\ \text { Beverages } & \text { Electronics } & \text { producers } & \text { services } \\\ \hline 170 & 46 & 59 & 56 \\\128 & 24 & 58 & 37 \\ 19 & 18 & 33 & 19 \\\ 16 & 14 & 31 & 19 \\ 12 & 13 & 28 & 17 \\ 11 & 12 & 22 & 15 \\ 10 & 10 & 16 & 15 \end{array} $$.

State three reasons why multiple \(t\) tests cannot be used to compare three or more means.

What are the assumptions for ANOVA?

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