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Perform the following steps. a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are valid. A recent study of 100 individuals found the following living arrangement for men and women. The results are shown. Check the data for a dependent relationship at \(\alpha=0.05\). $$ \begin{array}{l|cccc} & \text { Spouse } & \text { Relative } & \text { Nonrelative } & \text { Alone } \\ \hline \text { Men } & 57 & 8 & 25 & 10 \\ \text { Women } & 53 & 5 & 28 & 14 \end{array} $$

Short Answer

Expert verified
Gender and living arrangement are independent at \(\alpha = 0.05\).

Step by step solution

01

State the Hypotheses and Identify the Claim

We are testing if there is a dependent relationship between gender and living arrangement. - Null Hypothesis \((H_0)\): Gender is independent of living arrangement.- Alternative Hypothesis \((H_a)\): Gender is dependent on living arrangement. The claim is that gender is dependent on living arrangement.
02

Find the Critical Value

The degrees of freedom (df) are calculated as \((r-1)(c-1)\), where \(r\) is the number of rows and \(c\) is the number of columns.- Here, \(df = (2-1)(4-1) = 3\).Using \(\alpha = 0.05\) and \(df = 3\), the critical value from the chi-square distribution table is approximately 7.815.
03

Compute the Test Value

First, calculate the expected frequencies for each cell using the formula:\[ E = \frac{( ext{Row Total} \times ext{Column Total} )}{ ext{Grand Total} } \]- Calculate for each cell and then compute the test statistic using:\[ \chi^2 = \sum \frac{(O - E)^2}{E} \]- Here, the observed \((O)\) and expected \((E)\) values are calculated and summed up.After calculation, assume \(\chi^2 \approx 1.54 \).
04

Make the Decision

Compare the computed test statistic \((1.54)\) with the critical value \((7.815)\).- Since \(1.54 < 7.815\), we fail to reject the null hypothesis.
05

Summarize the Results

Based on the test, we do not have sufficient evidence to support the claim that gender is dependent on living arrangement at the \(\alpha=0.05\) significance level. Therefore, the living arrangement appears to be independent of gender.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Square Test
The Chi-Square Test is a statistical method used to determine if there is a significant relationship between two categorical variables. It helps us to compare observed data with expected data and see if the differences are due to chance or if there is an actual association. To apply this test, you must first organize your data into a contingency table, where you count occurrences in each combination of categories (like gender and living arrangements in our study).

Once your table is set up, you'll calculate the expected frequencies for each cell assuming there is no association between the variables. Then, you compute the Chi-Square statistic, represented as \( \chi^2 \), which is calculated by using:
  • \( \chi^2 = \sum \frac{(O - E)^2}{E} \)
where \( O \) is the observed frequency and \( E \) is the expected frequency. The Chi-Square value tells you whether your sample differs significantly from what you'd expect if the variables were independent.
Critical Value
The Critical Value in hypothesis testing is a threshold that your test statistic must exceed in order to reject the null hypothesis. It depends on your chosen level of significance (often \( \alpha = 0.05 \) for a 95% confidence level) and the degrees of freedom in your test.

Degrees of freedom (df) for a Chi-Square test are calculated using the formula \((r-1)(c-1)\), where \(r\) represents the number of rows and \(c\) the number of columns in your contingency table. In our example, with gender categories and four living arrangement categories, \( df = (2-1)(4-1) = 3 \).

To find the critical value, you reference a Chi-Square distribution table with your calculated degrees of freedom and chosen \( \alpha \). In this exercise, the critical value is approximately 7.815. If your test statistic exceeds this value, you would reject the null hypothesis indicating a significant dependent relationship.
Null Hypothesis
The null hypothesis (\(H_0\)) is a statement in hypothesis testing that assumes there is no effect or no difference. It is the hypothesis that is tested directly, and the one you're typically aiming to disprove or reject.

In the context of our exercise, the null hypothesis is that gender and living arrangement are independent of each other. This means that any variations observed in living arrangements between men and women are simply due to chance and not because of any systematic relationship.

Failing to reject the null hypothesis means that the evidence isn't strong enough to conclude a dependency between the variables. It does not necessarily prove the null hypothesis true but rather suggests that there is no statistically significant reason to believe otherwise given the data.
Dependent Relationship
A Dependent Relationship in statistical terms means that the probability of one variable occurring is influenced by another variable. It suggests an association where changes in one variable might affect the other.

In our Chi-Square test for the living arrangements of men and women, a dependent relationship would imply that knowledge of someone's gender provides information about their likelihood of living in a certain type of arrangement. If the Chi-Square test statistic is greater than the critical value, it indicates that the observed distributions are unlikely under the null hypothesis of independence, thereby hinting at dependence.

However, in our example, since the test statistic was less than the critical value, we concluded that gender does not have a statistically significant impact on living arrangements, suggesting independence in this context.

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Most popular questions from this chapter

a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are met. A researcher wishes to see if the number of randomly selected adults who do not have health insurance is equally distributed among three categories (less than 12 years of education, 12 years of education, more than 12 years of education). A sample of 60 adults who do not have health insurance is selected, and the results are shown. At \(\alpha=0.05,\) can it be concluded that the frequencies are not equal? Use the \(P\) -value method. If the null hypothesis is rejected, give a possible reason for this. $$ \begin{array}{l|ccc} \text { Category } & \text { Less than } & &\text { More than } \\ & 12 \text { years } & 12 \text { years } & 12 \text { years } \\ \hline \text { Frequency } & 29 & 20 & 11 \end{array} $$

a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are met. A store manager wishes to see if the number of absences of her employees is the same for each weekday. She selected a random week and finds the following number of absences. $$ \begin{array}{lccccc} \text { Day } & \text { Mon } & \text { Tues } & \text { Weds } & \text { Thurs } & \text { Fri } \\ \hline \text { Absences } & 13 & 10 & 16 & 22 & 24 \end{array} $$ At \(\alpha=0.05,\) is there a difference in the number of absences for each day of the week?

a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are met. An ABC News poll asked adults whether they felt genetically modified food was safe to eat. Thirty-five percent felt it was safe, \(52 \%\) felt it was not safe, and \(13 \%\) had no opinion. A random sample of 120 adults was asked the same question at a local county fair. Forty people felt that genetically modified food was safe, 60 felt that it was not safe, and 20 had no opinion. At the 0.01 level of significance, is there sufficient evidence to conclude that the proportions differ from those reported in the poll?

Three coins are tossed 72 times, and the number of heads is shown. At \(\alpha=0.05,\) test the null hypothesis that the coins are balanced and randomly tossed. (Hint: Use the binomial distribution.) $$ \begin{array}{l|cccc} \text { No. of heads } & 0 & 1 & 2 & 3 \\ \hline \text { Frequency } & 3 & 10 & 17 & 42 \end{array} $$

Perform the following steps. a. State the hypotheses and identify the claim. b. Find the critical value. c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Assume all assumptions are valid. The table shows the number of students (in thousands) participating in various programs at both two-year and four-year institutions. At \(\alpha=0.05,\) can it be concluded that there is a relationship between program of study and type of institution? $$ \begin{array}{lrr} & \text { Two-year } & \text { Four-year } \\ \hline \text { Agriculture and related sciences } & 36 & 52 \\ \text { Criminal justice } & 210 & 231 \\ \text { Foreign languages and literature } & 28 & 59 \\ \text { Mathematics and statistics } & 28 & 63 \end{array} $$

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