91Ó°ÊÓ

The given graph is:

Subtracting the smaller area from the bigger area yields the area under the normal curve between two specified $z-$scores.

There is an area between two $z-$scores equal to the larger of the two supplied areas minus the smaller of the two given areas.

Thus, the area under the standard normal curve to the left of $1.96$ is $0.9750$, whereas the area under the standard normal curve to the left of $-1.96$ is $0.0250$.

As a result, the area between $-1.96$and $1.96$under the usual normal will be $0.9750-0.0250=0.9500.$

So, the shaded area is$0.9500$

The given graph is:

Subtracting the smaller area from the bigger area yields the area under the normal curve between two specified $z-$scores.

There is an area between two $z-$scores equal to the larger of the two supplied areas minus the smaller of the two given areas.

Thus, the area under the standard normal curve to the left of $2.33$is $0.9901$, whereas the area under the standard normal curve to the left of $-2.33$is $0.0099$

As a result, the area between $-2.33$and $2.33$under the usual normal will be $0.9901-0.0099=0.9802$

So, the shaded area is$0.9802$

The given graph is:

To the left of $-1.28$, the area under the standard normal curve is $0.1003.$

The given graph is:

To the left of $-1.64$, the area under the standard normal curve is $0.0505$

$Areatotheright=1-Areatotheleft$

To the left of $-1.64$, the area under the standard normal curve is $0.9495$$0.9495$.

$1-0.9495=0.0505$ is the area to the right of $1.64$

As a result, the area beneath the standard normal to the left of$-1.64$and to the right of$1.64$will be$0.0505+0.0505=0.1010.$