91Ó°ÊÓ

Under the standard normal, calculate the area lying to the right of$-1.07$

Right-hand area = $1-$Left-hand area

Because the given number $-1.07$is negative, the conventional normal table of negative $z$scores is applied.

First, go down to $-1.0$in the right-hand column labeled $\text{'}z,\text{'}$and then across the row to the right.

As a result, the area to the right of $-1.07$under the standard normal is $1-0.1423=0.8577.$

Under the standard normal, calculate the area lying to the right of$0.6$

Right-hand area $=1-$Left-hand area

Because the given quantity $0.6$is positive, the typical normal table of positive $z$scores is employed. First, move down to $0.6$in the left hand column labeled $z$and then across the row to the column labeled $0.00$to get $0.7257.$

As a result, the area beneath the standard normal to the right of $0.6$is $1-0.7257=0.2743$

Under the standard normal, calculate the area lying to the right of$0$.

Right-hand area $=1-$Left-hand area

The typical table is employed. To begin, move down the left hand column labeled' $\text{'}z\text{'}$to $0.0$and then across the row to the column labeled $\text{'}0.00\text{'}$to get $0.5000$.

As a result, the area beneath the standard normal to the right of $0$is $1-0.5000=0.5000$.

Under the standard normal, calculate the area lying to the right of$4.2$.

Right-hand area $=1-$Left-hand area

The typical table is employed. To begin, move down the left hand column labeled' $z$' to $4.0$and then across the row to the column labeled' $0.02$to get $1.0000$.

As a result, the area beneath the standard normal to the right of $0.42$is $1-1.0000=0.0000.$