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In each of Exercises 14.64-14.69, apply Procedure 14.2 on page 567 to find and interpret a confidence interval, at the specified confidence level, for the slope of the population regression line that relates the response variable to the predictor variable.
14.65 Corvette Prices. Refer to Exercise 14.59;90%

Short Answer

Expert verified

The Confidence interval at90% is [71.0382,85.8079].

Step by step solution

01

Given information

To determine 90%confidence interval that refer to Exercise 14.59.

02

Explanation

The provided sample data as follows:

x
12
24
10
9
15
17
9
18
16
22
y
84
79
81
90
81
85
82
84
83
75

Determine the degree of freedom as follows:
df=n-2

=10-2

=8
The value of t0.1is 1.860, as determined by the student t-test.

Determine the confidence interval as follows:

x¯-t0.1×sn=82.4-1.860×3.949710

=71.0382

x¯-t0.1×sn=82.4+1.860×3.949710

=85.8079

Finally,

Confidence interval=[71.0382,85.8079].

03

Explanation

Plot a graph as follows:

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