/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 10.62 Simulation. In this exercise, y... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simulation.In this exercise, you are to perform a compute simulation to illustrate the distribution of the pooled t-statistic, given in Key Fact 10.2on page 407.

a. Simulate 1000random samples of size 4from a normally distributed variable with a mean of 100and a standard deviation of 16. Then obtain the sample mean and sample standard deviation of each of the 1000samples.

b. Simulate 1000random samples of size 3from a normally distributed variable with a mean of 110and a standard deviation of 16Then obtain the sample mean and sample standard deviation of each of the1000samples.

c. Determine the value of the pooled t-statistic for each of the 1000pairs of samples obtained in parts aand b.

d. Obtain a histogram of the 1000values found in part c.

e. Theoretically, what is the distribution of all possible values of the pooled t-statistic?

f. Compare your results from partsdande.

Short Answer

Expert verified

Part a: The mean and standard deviation of each of the 1000samples is, t=x-1-x-2sP1n1+1n2.

Part b: The mean and standard deviation of each of the 1000samples is, t=x-1-x-2sP14+13.

Part c: The value of the pooled t-statistic for each of the 1000pairs of samples obtained in parts aand bis, 96.062.

Part d: A histogram for the pooled t-statistic:

Part e: The distribution of all possible values of the pooled t-statistic is, 96.062.

Partf: We observed that the pooled t-statistics for 1000pairs of random samples satisfying normality condition, which was shown in the histogram.

Step by step solution

01

Part a Step 1. Given information

We need to simulate1000random samples of size4from a normally distributed variable with a mean of100and a standard deviation of16.

02

Part a Step 2. Now we need to obtain the mean and standard deviation of each of the 1000 samples are shown in the last two columns of the table.

t=x-1-x-2sP1n1+1n2.

03

Part b Step 1. Here, we need to simulate 1000 random samples of size 4 from a normally distributed variable.

Also, the mean is, 100and the standard deviation is, 16. We need to obtain the mean and standard deviation of each of the 1000samples are shown in the last two columns of the table.

33.

t=x-1-x-2sP14+13.

04

Part c Step 1. Pooled t-statistic is, 

t=x-1-x-2sP712sP=n1-1s12+n2-1s22n1+n2-2=4-1s12+3-1s224+3-2sP=3s12+2s225=n1-1s12+n2-1s22n1+n2-2

05

Part c Step 2. we obtain the pooled t-statistic for each of the 1000 pairs of the samples obtained in parts a and b which are shown:

sP=4-189.12+3-1105.64824+3-2=96.062

06

Part d Step 1. Let us draw a histogram for the pooled t-statistic:

07

Part e Step 1. Theoretically, the distribution of all the possible values of the pooled t-statistic is obtained by,

sP=89.1-105.64896.06214+13=-0.22556=96.062

Now apply the same procedure for the remaining999pairs of values.

08

Part f Step 1. Now compare the results from the part d and e. 

We observed that the pooled t-statistics for 1000pairs of random samples satisfying normality condition, which was shown in the histogram.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 413, the following relationship holds between hypothesis tests and confidence intervals: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ1=μ2will be rejected in favor of the alternative hypothesis Ha:μ1≠μ2if and only if the ( 1-α)-level confidence interval for μ1-μ2does not contain 0. In each case, illustrate the preceding relationship by comparing the reults of the hypothesis test and confidence interval in the specified xercises.

a. Exercises 10.48 and 10.54.

b. Exercises 10.49 and 10.55.

A variable of two populations has a mean of 7.9and a standard deviation of 5.4for one of the populations and a mean of 7.1and a standard deviation of 4.6for the other population. Moreover. the variable is normally distributed in each of the two populations.

a. For independent samples of sizes 3and 6, respectively, determine the mean and standard deviation of x1-x2.

b. Can you conclude that the variable x1-x2is normally distributed? Explain your answer.

c. Determine the percentage of all pairs of independent samples of sizes 4and 16, respectively, from the two populations with the property that the differencex1-x2 between the simple means is between -3and 4.

Give an example of interest to you for comparing two population means. Identify the variable under consideration and the two populations.

The primary concern is deciding whether the mean of Population 1 is less than the mean of Population 2.

In each of Exercises 10.75-10.80, we have provided summary statistics for independent simple random samples from non populations. In each case, use the non pooledt-test and the non pooled t-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.

x~1=10,s1=2,n1=15,x~2=12,s2=5,n2=15

a. Two-tailed testα=0.05.

b. 95%confidence interval.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.