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Obtain a sample size

Margin of error =0.02

Confidence level =95%

Likely range 0.4-0.7

Short Answer

Expert verified

The required sample size is2,401.

Step by step solution

01

Given information

Obtain a sample size

Margin of error 0.02

Confidence level =95%

Likely range 0.4-0.7

02

Explanation

From the given values

When the margin of error is 0.02and the confidence level is 95%, calculate the sample size.

With a 95%confidence level, the required value of za2from table areas under the standard normal curve is 1.96

Usepg'=0.5because the value in the range closet to0.5.

The sample size is

n=0.25za2E2

=0.251.960.022

=0.25(9,604)

=2,401.

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Most popular questions from this chapter

The Quinnipiac University Poll conducts nationwide surveys as a public service and for research. In one poll. participants were asked whether they thought eliminating the federal gas tax for the summer months is a good idea. The following problems are based on the results of that poll.

a. Of611Republicans, 275thought it a good idea, and, of 872Democrats, 366thought it a good idea. Obtain a 90%confidence interval for the difference between the proportions of Republicans and Democrats who think that eliminating the federal gas tax for the summer months is a good idea.

b. Of 907women,417thought it a good idea, and, of 838men, 310thought it a good idea. Obtain a90% confidence interval for the difference between the percentages of women and men who think that eliminating the federal gas tax for the summer months is a good idea.

a. Determine the sample proportion.

b. Decide whether using the one-proportion z-test is appropriate.

c. If appropriate, use the one-proportion z-test to perform the specified hypothesis test.

x=40

n=50

H0:p=0.6

Ha:p>0.6

α=0.01

Use your result from Exercise 11.132to show that a (1-α)level confidence interval for the difference between two population proportions that has a margin of error of at most Ecan be obtained by choosing

n1=n2=0.5zα/2E2

rounded up to the nearest whole number.

Getting a Job. The National Association of Colleges and Employers sponsors the Graduating Student and Alumni Survey. Part f the survey gauges student optimism in landing a job after graduation. According to one year's survey results, published in American Demographics, the 1218respondents, 733 said that they expected difficulty finding a job. Note: In this problem and the next, round your proportion answers to four decimal places.

a. Use these data to find and interpret a 95% confidence interval for the proportion of students who expect difficulty finding a job.

b. Find the margin of error for the estimate of p.

c. Express the confidence interval in the form point estimate ± margin of error.

Fill in the blanks.

a. The mean of all possible sample proportions is equal to the

b. For large samples, the possible sample proportions have approximately a distribution.

c. A rule of thumb for using a normal distribution to approximate the distribution of all possible sample proportions is that both and are or greater.

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