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Buckling Up. Refer to Exercise 11.109and find and interpret a 99%confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups 16-24 years and 25-69 years.

Short Answer

Expert verified

There is 99% interval for the difference between the proportion is (-0.0937,-0.0063)

Step by step solution

01

Given Information

The given values are,

n1=1000,n2=1100,p~1=0.790,p~2=0.840.

02

Explanation

The formula for z, is given by,

z=p~1-p~2p~p1-p~p1n1+1m2

The required value ofza2with 99%confidence level is 2.575.

The 98%confidence interval is.

p~1-p~2±za2p~11-p~1n1+p~11-p~1n2=(0.790-0.840)

±2.5750.790(1-0.790)1000+0.840(1-0.840)1100

=-0.05±0.0437

=(-0.0937,-0.0063)

Therefore, there is 99%interval for the difference between the proportion is (-0.0937,-0.0063)

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Most popular questions from this chapter

In this Exercise, we have given the number of successes and the sample size for a simple random sample from a population. In each case,

a. use the one-proportion plus-four z-interval procedure to find the required confidence interval.

b. compare your result with the corresponding confidence interval found in Exercises 11.25-11.30, if finding such a confidence interval was appropriate.

x=40,n=50,95%level

We have given a likely range for the observed value of a sample proportionp^

0.2orless

a. Based on the given range, identify the educated guess that should be used for the observed value of p^to calculate the required sample size for a prescribed confidence level and margin of error.

b. Identify the observed values of the sample proportion that will yield a larger margin of error than the one specified if the educated guess is used for the sample-size computation.

Explain the relationships among the sample proportion, the number of successes in the sample, and the sample size.

A poll by Gallup asked, "If you won 10 million dollars in the lottery, would you continue to work or stop working?' Of the 1039 American adults surveyed, 707 said that they would continue working. Obtain a 95% confidence interval for the proportion of all American adults who would continue working if they won 10 million dollars in the lottery.

In discussing the sample size required for obtaining a confidence interval with a prescribed confidence level and margin of error, we made the following statement: "... we should be aware that, if the observed value of p^is closer to 0.5than is our educated guess, the margin of error will be larger than desired." Explain why.

One-Proportion Plus-Four z-Interval Procedure. To obtain a plus four z-interval for a population proportion, we first add two successes and two failures to our data (hence, the term "plus four") and then apply Procedure 11.1on page 454to the new data. In other words, in place of p^(which is x/n), we use p~=(x+2)/(n+4). Consequently, for a confidence level of 1-α, the endpoints of the plus-four z-interval are

p~±za/2·p~(1-p~)/(n+4)

As a rule of thumb, the one-proportion plus-four z-interval procedure should be used only with confidence levels of 90% or greater and sample sizes of 10 or more.

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