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Refer to Exercise 9.18. Explain what each of the following would mean.

(a) Type I error.

(b) Type II error.

(c) Correct decision.

Now suppose that the results of carrying out the hypothesis test lead to the rejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean age at diagnosis of all people with early-onset dementia.

(d) is 55 years old.

(e) is less than 55 years old.

Short Answer

Expert verified

(a) Rejecting a Null Hypothesis, when it is true.

(b) Rejecting a Null Hypothesis, when H0is false.

(c) If the true null hypothesis is not rejected or a false null hypothesis is rejected.

(d) Correct Decision.

(e) Type II error.

Step by step solution

01

Step 1. Given Information.

The null hypothesis is,

H0:μ=55years.

The alternative hypothesis is,

H0:μ<55years.

02

Part (a). Type I error.

According to the definition of the type I error it is to reject a null hypothesis when it is true. A type I error would occur in fact H0:μ=55yearstrue, that is the mean age at diagnosis of all people with early-onset dementia is 55yearsold, but the results of the sampling lead to conclude that the mean age at diagnosis of all people with early-onset dementia is less than55yearsold.

03

Part (b). Type II error.

According to the definition of the type II error, it is to not reject a null hypothesis when it H0is false. A type II error would occur in fact μ=55years is not to be rejected, but the results of the sampling fall to lead to conclude that the mean age at diagnosis of all people with early-onset dementia is55years old.

04

Part (c). Correct Decision.

A correct decision would occur if the true null hypothesis is not rejected or a false null hypothesis is rejected. Here, in the fact the mean RDA of adult females is and the results of the sampling do not lead to rejection, so is a correct decision; or the mean RDA of adult males is and the results of the sampling lead to that conclusion.

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Most popular questions from this chapter

Purse Snatching. The Federal Bureau of Investigation (FBI) compiles information on robbery and property crimes by type and selected characteristic and publishes its findings in Uniform Crime Reports. According to that document, the mean value lost to purse snatching was 468in 2012. For last year, 12randomly selected purse-snatching offenses yielded the following values lost, to the nearest dollar.

Use a t-test to decide, at the5%significance level, whether last year's mean value lost to purse snatching has decreased from the 2012mean. The mean and standard deviation of the data are 455.0and 86.8, respectively.

We have been provided a sample mean, sample size, and population standard deviation. In the given case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level.

x¯=24,n=15,σ=4,H0:μ=22,Ha:μ>22

As we mentioned on page 378, the following relationship holds between hypothesis test and confidence intervals for one-mean z-procedures: For a two-tailed hypothesis test at the significance level α, the null hypothesis role="math" localid="1653038937481" H0:μ=μ0will be rejected in favor of the alternative hypothesis Ha:μ≠μ0if and only if μ0lies outside the 1-α-level confidence interval for μ. In each case, illustrate the preceding relationship by obtaining the appropriate one-mean z-interval and comparing the result to the conclusion of the hypothesis test in the specified exercise.

Part (a): Exercise 9.84

Part (b): Exercise9.87

In each of Exercises 9.41-9.46 ,determine the critical values for a one-mean z-test. For each exercise, draw a graph that illustrates your answer

A right- tailed test withα=0.01

In each of Exercises 9.41-9.46 ,determine the critical values for a one-mean z-test. For each exercise, draw a graph that illustrates your answer

A left-tailed test withα=0.05

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