91Ó°ÊÓ

The Null Hypothesis is,

$H_0:\mathrm{μ}=23$.

The Alternative Hypothesis is,

$H_0:\mathrm{μ}≠23$.

This is the error committed to rejecting a null hypothesis $\left(H_0\right)$when it is true.

The conclusion is that the mean location period of grey seals differs from $23$days but in reality, the mean location period of grey seals does not differ from$23$days.

This is the error committed to accepting a null hypothesis $\left(H_0\right)$when it is false.

The conclusion is that the mean location period of grey seals does not differ from $23$days but in reality, the mean location period of grey seals differs from $23$days.

The following are the two ways of making the correct decision:

1. If $H_0$is true, then do not reject $H_0$.
2. If $H_0$is false, then reject $H_0$.

If the mean location period of grey seals does not differs from $23$days, $\mathrm{μ}=23days$, then the null hypothesis is not rejected.

If the mean location period of grey seals differs from$23$days,$\mathrm{μ}≠23days$, then the null hypothesis is rejected.

In this situation, a Type I error is committed.

The null hypothesis is not rejected because the mean location period of grey seals equals to $23$days since the mean location period of grey seals equals to $23$days.

In this situation, a Type II error is committed.

The null hypothesis is rejected because the mean location period of grey seals is not equals to $23$days since the mean location period of grey seals differs from$23$ days.