91Ó°ÊÓ

We are given that the y-intercept is $-3$ and slope is $4$ and we have to find out about the slope nature.

Now, as we know that the given slope is$4$i.e., it is positive which means that y-value increases by $4$for every increase in x by $1$unit and whenever the slope will be positive it will be upward as it always increase the value of y.

Hence, the slope is upward.

We are given that the y-intercept is $-3$and slope is $4$and we have to find out about the slope nature.

Now, as we know that the general equation of line is

$y=mx+c$let this be equation 1....

where m is the slope and c is the y-intercept.

and as we are given that slope is$4$and y-intercept is $-3$.

put these value in equation 1...

we get,$y=4x-3$

Hence, this is the required equation.

We are given that the y-intercept is $-3$ and slope is $4$ and we have to find out about the slope nature.

Now, we have find out the equation in part (b)

which is$y=4x-3$

To find out the points it should satisfy the equation..

Case I-

Put x=$0$and find the value of y,

we get localid="1650836146737" $y=4\left(0\right)-3=3$so, the point is localid="1650836151611" $(0,3)$.

Case II-

Put y=localid="1650836157042" $11$and find the value of x.

we get localid="1650836161559" $11=4x-3$

rearranging localid="1650836165761" $x=2$so, the point islocalid="1650836170025" $(2,11)$

Now plot these two points on the graph

Hence this is the required graph.