/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 3.203 We have provided simple data set... [FREE SOLUTION] | 91影视

91影视

We have provided simple data sets for you to practice the basics of finding

(a) Population mean

(b) Population standard deviation

Data is1,2,4,4

Short Answer

Expert verified

(a) Population Mean()=2.75

(b) Population Standard deviation()= 1.299

Step by step solution

01

Part(a) Step 1: Given Information

We are given simple data set of1,2,4,4

We need to find population mean of given data

02

Part(a) Step 2: Simplify 

A population in statistics is a group of similar items or events that relate to a query or experiment.

Population Mean()=xiN

xidenotes individual value

Ndenotes total population

=1+2+4+44=114=2.75

Hence, mean of given data is 2.75

03

Part (b) Step 1:Given Information

We are provided simple data having1,2,4,4

We need to find standard deviation of given population.

04

Part(b) Step 2: Simplify

We know standard deviation is square root of variance.

Formula of variance is

()2=(x1-)2+............+(xN-)2N

Where xidenotes ithvalue

denotes population mean

Ndenotes total population

Using above formula,

=(1-2.75)2+(2-2.75)2+(4-2.75)2+(4-2.75)24=1.688=1.299

Hence, population standard deviation of given data is1.299

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Name and describe the three most important measures of center.

A quantitative data set has size 60. At least how many observations lie within three standard deviation to either side of the mean ?

Copperhead and Tiger Snakes. S. Fearn et al. compare two types of snakes in the article 鈥淏ody Size and Trophic Divergence of Two Large Sympatric Elapic Snakes in Tasmania鈥 (Australian Journal of Zoology, Vol. 60, No. 3, pp. 159-165). Tiger snakes and lowland copperheads are both large snakes confined to the cooler parts of Tasmania. The weights of the male lowland copperhead in Tasmania have a mean of 812.07 g and a standard deviation of 330.24 g; the weights of the male tiger snake in Tasmania have a mean of 743.65 g and a standard deviation of 336.36 g.
a. Determine the z-scores for both a male lowland copperhead snake and a male tiger snake whose weights are 850 g.
b. Under what conditions would it be reasonable to use z-scores to compare the relative standings of the weights of the two snakes?
c. Assuming that a comparison using z-scores is legitimate, relative to the other snakes of its type, which snake is heavier?

Find the

a. Mean b. median c. models

For the mean and the median, round each answer to one more decimal place than that used for the observations.

Amphibian Embryos. In a study of the effects of radiation on amphibian embryos titled "Shedding Light on Ultraviolet Radiation and Amphibian Embryos" L. Licht recorded the time it took for a sample of seven different species of frogs' and toads' eggs to hatch. The following table shows the times to hatch, in days.

6,7,11,6,5,5,11

Simple data sets have been given for you to try locating the descriptive metrics mentioned in this section. For each data set separately.

(a) Calculate the quartiles,

(b) calculate the interquartile range

(c)compile a five-number summary.

1,2,3,4,5,1,2,3,4,5

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.