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We have been given that the data set has mean, $\hat{x}=10$and standard deviation, $s=3$.

We need to find out upper observation limit and lower observation limit.

Chebyshev's rule states that for any quantitative data collection with a real number $k$higher than or equal to $1$, at least $1-\frac{1}{k^2}$of the observations are within standard deviations of the mean, that is, $\hat{x}-ks$and $\hat{x}+ks$.

By Chebyshev's rule,

$$\begin{gathered} 1-\frac{1}{k^2}=75\% \\ 1-\frac{1}{k^2}=\frac{75}{100} \\ 1-\frac{1}{k^2}=\frac{3}{4} \\ \frac{1}{k^2}=1-\frac{3}{4} \\ \frac{1}{k^2}=\frac{1}{4} \\ {k}^2=4 \\ k=2 \end{gathered}$$

Neglecting negative value as $k$should be greater than $1$.

Now,

Upper limit$=\hat{x}+k\left(s\right)=10+2脳3=16$

Lower limit$=\hat{x}-k\left(s\right)=10-2脳3=4$

We have been given that the data set has mean, $\hat{x}=10$and standard deviation, $s=3$..

We need to find out what percent of the data set lies between $1$and $19$.

Chebyshev's rule states that for any quantitative data collection with a real number $k$ higher than or equal to $1$, at least$1-\frac{1}{k^2}$ of the observations are within standard deviations of the mean, that is,$\hat{x}-ks$ and $\hat{x}+ks$.

By Chebyshev's rule,

Lower limitrole="math" localid="1651220913088" $=\stackrel{铃�}{x}-k\left(s\right)$

role="math" $$\begin{gathered} 1=10-k脳3 \\ 3k=9 \\ k=3 \end{gathered}$$

Percentage$=1-\frac{1}{k^2}=1-\frac{1}{9}=\frac{8}{9}=88.89\%$