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American Alligators. Refer to Exercise 8.78.

a. Determine the margin of error for the 95%confidence interval.

b. Determine the margin of error for the 99%confidence interval.

c. Compare the margins of error found in parts (a) and (b).

d. What principle is being illustrated?

Short Answer

Expert verified

(a) The margin of error for 95%confidence interval is 23.77seconds.

(b) The margin of error for role="math" localid="1652809930152" 99%confidence interval is 31.23seconds.

(c) Margin of error of 95%confidence level is smaller than that of 99%confidence level.

(d) Same sample size and increased confidence level.

Step by step solution

01

Given Information

From previous exercise, 95%confidence level of μis (314.23,361.77).

99%confidence level ofμis(306.77,369.23)

02

Margin of Error for 95% Confidence Interval

Margin of error is calculated as:

E=Upperlimit-Lowerlimit2

E=361.77-314.232

E=47.542

E=23.77seconds

03

Margin of Error for 99% Confidence Interval

Margin of Error is given by

Margin of error=Upper limit-Lower limit2

E=369.23-306.772

E=62.462

E=31.23seconds

04

Comparison of the margins of error found above

It is found from above results that confidence interval of 95%has smaller margin of error than that of99%confidence interval.

05

Principle Illustrated

The principle illustrated is:

When sample size is same and confidence level is increased, margin of error increases.

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Most popular questions from this chapter

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