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Distribution 0.5,0.3,0.2.

observed frequencies 45,39,16.

Significant levelα=0.01.

Short Answer

Expert verified

The variable has a given distribution0.5,0.3,0.2.

Step by step solution

01

Given Information

Given data:

Distribution 0.5,0.3,0.2.

observed frequencies 45,39,16.

Significant level α=0.01.

02

Explanation

To find the goodness fit test,

No. of. Sample size n=45+39+16

n=100.

Observed frequencies453916Relative frequenciesp0.50.30.2Expected frequenciesnp503020(obs-exp)2exp0.52.90.8χ2=∑(obs-exp)2exp=4.2

The degree of freedom,

=k-1

=3-1

=2

03

Explanation

The critical value, with 2dfis χ0,012=9.210

χ2=4.2<χ20,05=9.210

Because it isn't available in the rejection area. So the Null hypothesis is accepted.

As a result, the variable has a defined area.

The Pvalue is:0.010

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