/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} 12.83 Fear of Gangs. In the article "G... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Fear of Gangs. In the article "Growing Pains and Fear of Gangs" (Applied Psychology in Criminal Justice, Vol. 5, No. 2, pp. 139-164), B. Brown and W. Benedict examined the relationship between worry about a gang attack and actually being a victim of a gang attack. Interviews of a sample of high school students yielded the following contingency table.

Short Answer

Expert verified

The data provide sufficient evidence to conclude that an association exists between worry about a gang attack and actually being a victim of a gang attack at the 1% significance level.

Step by step solution

01

Step 1. Given information

02

Step 2. 

Check whether or not the data provide sufficient evidence to conclude that an association exists between worry about a gang attack and actually being a victim of a gang attack.

Step 1:

The test hypotheses are given below:

Null hypothesis:

H0 : There is no association exists between worry about a gang attack and actually being a victim of a gang attack.

Alternative hypothesis:

H1 : There is an association exists between worry about a gang attack and actually being a victim of a gang attack.

Step 2: Decide the level of significance.

Here, the level of significance is, 1%

Step 3:

Find the expected frequency and test statistic.

MINITAB procedure:

Step 1: Choose Stat > Tables > Chi-Square test for association.

Step 2: In Columns containing the table, enter the column of Yes and No.

Step 3: In Rows, select Victim.

Step 4: Under Statistics, select Chi-square test, Display counts in each cell, Display marginal counts and expected cell counts.

Step 5: Click OK.

Now,

Minitab output

Pearson Chi-Square =23.455,DF=1,p-Value=0.000

Likelihood Ratio Chi-Square=19.841, DF=1, p-Value =0.000

From the MINITAB output, the value of the chi-square statistic is 23.455.

Step 4:

Find the p-value.

From the MINITAB output, the p-value is 0.000

Step 5:

Rejection rule:

If , then reject the null hypothesis.

Here, the P-value is lesser than the level of significance.

That is, P-value (=0.000)<alpha(=0.01).

Therefore, the null hypothesis is rejected at 1 % level.

Thus, the results are statistically significant at 1% level of significance.

The data provide sufficient evidence to conclude that an association exists between worry about a gang attack and actually being a victim of a gang attack at the 1% significance level.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How do you identify different chi-square distributions?

12.81 Learning at Home. M. Stuart et al. studied various aspects of grade-school children

and their mothers and reported their findings in the article "Learning to Read at Home

and at School" (British Journal of Educational Psychology, 68(1), pp. 3-14).

The researchers gave a questionnaire to parents of 66 children in kindergarten

through second grade. Two social-class groups, middle and working, were identified based on the mother's occupation.

a. One of the questions dealt with the children's knowledge of nurs-

In each of the given Exercises, we have presented a contingency table that gives a cross-classification of a random sample of values for two variables, x, and y, of a population. For each exercise, perform the following tasks.

a. Find the expected frequencies. Note: You will first need to compute the row totals, column totals, and grand total.

b. Determine the value of the chi-square statistic.

c. Decide at the 5% significance level whether the data provide sufficient evidence to conclude that the two variables are associated.

12.50 U.S. Hospitals. The American Hospital Association publishes 12.30 U.S. information about U.S. hospitals and nursing homes in Hospital Statistics. The following contingency table provides a cross classification of U.S. hospitals and nursing homes by type of facility and number of beds.

In the following questions, the term hospital refers to either a hospital or nursing home.


24 or fewer25-7475 or moreTotal
General260158635575403
Psychiatric24242471737
Chronic132236
Tuberculosis0224
Other25177208410
Total310201042606580

a. How many hospitals have at least 75 beds?

b. How many hospitals are psychiatric facilities?

c. How many hospitals are psychiatric facilities with at least 75 beds?

d. How many hospitals either are psychiatric facilities or have at least 75 beds?

e. How many general facilities have between 25 and 74 beds?

f. How many hospitals with between 25 and 74 beds are chronic facilities?

g. How many hospitals have more than 24 beds?

Job Satisfaction. A CNN/USA TODAY poll conducted by Gallul asked a sample of employed Americans the following question: "Which do you enjoy more, the hours when you are on your job, or the hours when you are not on your job?" The responses to this question were cross-tabulated against several characteristics, among which were gender, age, type of community, educational attainment, income, and type of employer. The data are provided on the WeissStats site. In each of Exercises 12.87-12.92, use the technology of your choice to decide, at the 5% significance level, whether an association exists between the specified pair of variables.

Educational attainment and response

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.