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Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, or critical value(s), then the conclusion about the null hypothesis, as well as the final conclusion that address the original claim. Assume that a simple random sample is selected from a normally distributed population.

Birth Weights A simple random sample of birth weights of 30 girls has a standard deviation of 829.5 hg. Use a 0.01 significance level to test the claim that birth weights of girls have the same standard deviation as birth weights of boys, which is 660.2 hg (based on Data Set 4 鈥淏irths鈥 in Appendix B).

Short Answer

Expert verified

The hypotheses are as follows.

\(\begin{array}{l}{H_0}:\sigma = 660.2\\{H_1}:\sigma \ne 660.2\end{array}\)

The test statistic\({\chi ^2} = 45.78\), and the critical values are 52.336 and 13.121.

The null hypothesis is failed to be rejected.

There is sufficient evidence to support the claim that the standard deviation of the birth weights of girls is equal to that of the birth weights of boys.

Step by step solution

01

Given information

The standard deviation of the birth weights for 30 girls is 829.5 hg.

The level of significance is 0.01 to test the claim that both girls and boys have the same standard deviation of birth weights, which is 660.2 hg.

02

State the hypotheses

To test the claim that the birth weights of girls have the same standard deviation as the birth weights of boys, the null and alternative hypotheses are formulated as follows.

\(\begin{array}{l}{H_0}:\sigma = 660.2\\{H_1}:\sigma \ne 660.2\end{array}\)

Here, \(\sigma \) is the true standard deviation of the birth weights for girls.

03

State the test statistic

The test statistic\({\chi ^2}\)with\(\left( {n - 1} \right)\)degrees of freedom is given as follows.

\(\begin{array}{c}{\chi ^2} = \frac{{\left( {n - 1} \right){s^2}}}{{{\sigma ^2}}}\\ = \frac{{\left( {30 - 1} \right){{\left( {829.5} \right)}^2}}}{{{{\left( {660.2} \right)}^2}}}\\ = 45.7804\end{array}\).

The degree of freedom is computed as follows.

\(\begin{array}{c}df = n - 1\\ = 30 - 1\\ = 29\end{array}\)

Thus, the test statistic is 45.78 with 29 degrees of freedom.

04

State the critical values

The test is two-tailed.

The critical values are\({\chi ^2}_L,{\chi ^2}_R\),such that

\(\begin{array}{l}P\left( {{\chi ^2} < {\chi ^2}_L} \right) = \frac{{0.01}}{2}\left( {0.005} \right)\\P\left( {{\chi ^2} > {\chi ^2}_L} \right) = 0.995\\P\left( {{\chi ^2} > {\chi ^2}_R} \right) = \frac{{0.01}}{2}\left( {0.005} \right)\end{array}\)

Using the chi-square table for 29 degrees of freedom and a 0.005 level of significance, the right-tailed critical value is 52.336, and the left-tailed one is 13.121.

Thus,

\(\begin{array}{l}\chi _L^2 = 13.121\\\chi _R^2 = 52.336\end{array}\)

05

State the decision

The decision rule states the following:

If the test statistic lies between the critical values, the null hypothesis will fail to be rejected; otherwise, it will be rejected.

In this case, the test statistic lies between the critical values, and hence, the null hypothesis is failed to be rejected at a 0.01 level of significance.

Thus, it can be concluded that there is sufficient evidence to support the claim that the standard deviation of the birth weights of girls is equal to the standard deviation of the birth weights of boys.

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Most popular questions from this chapter

In Exercises 9鈥12, refer to the exercise identified. Make subjective estimates to decide whether results are significantly low or significantly high, then state a conclusion about the original claim. For example, if the claim is that a coin favours heads and sample results consist of 11 heads in 20 flips, conclude that there is not sufficient evidence to support the claim that the coin favours heads (because it is easy to get 11 heads in 20 flips by chance with a fair coin).

Exercise 5 鈥淥nline Data鈥

Car Booster Seats The National Highway Traffic Safety Administration conducted crash tests of child booster seats for cars. Listed below are results from those tests, with the measurements given in hic (standard head injury condition units). The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.01 significance level to test the claim that the sample is from a population with a mean less than 1000 hic. Do the results suggest that all of the child booster seats meet the specified requirement?

774 649 1210 546 431 612

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Exercise 8- 5. Perception and Reality In a presidential election, 308 out of 611 voters surveyed said that they voted for the candidate who won (based on data from ICR Survey Research Group). Use a 0.05 significance level to test the claim that among all voters, the percentage who believe that they voted for the winning candidate is equal to 43%, which is the actual percentage of votes for the winning candidate. What does the result suggest about voter perceptions?

The P-value for a hypothesis test is 0.06. For each of the following significance levels, decide whether the null hypothesis should be rejected.

a. =0.05

b. =0.10

c.=0.06

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