91影视

There are 232 male deaths and 55 female deaths due to lightning strikes. It is claimed that the proportion of male deaths is greater than \[\frac{1}{2}\] or 0.5.

The null hypothesis is written as follows:

The proportion of male deaths is equal to 0.5.

\({H_0}:p = 0.5\)

The alternative hypothesis is written as follows:

The proportion of male deaths is greater than 0.5.

\({H_1}:p > 0.5\)

The test is right-tailed.

The sample size is computed below:

\(\begin{array}{c}n = 232 + 55\\ = 287\end{array}\)

The sample proportion of male deaths is equal to:

\[\begin{array}{c}\hat p = \frac{{{\rm{Number}}\;{\rm{of}}\;{\rm{male}}\;{\rm{deaths}}}}{{{\rm{Sample}}\;{\rm{size}}}}\\ = 0.808\end{array}\]

The population proportion of male deaths is equal to 0.5.

The value of the test statistic is computed below:

\(\begin{array}{c}z = \frac{{\hat p - p}}{{\sqrt {\frac{{pq}}{n}} }}\\ = \frac{{0.808 - 0.5}}{{\sqrt {\frac{{0.5\left( {1 - 0.5} \right)}}{{287}}} }}\\ = 10.44\end{array}\)

Thus, z=10.44.

Referring to the standard normal table, the critical value of z at\(\alpha = 0.01\)for a right-tailed test is equal to 2.3263.

Referring to the standard normal table, the p-value for the test statistic value of 10.44 is equal to 0.000.

Since the p-value is less than 0.01, the null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of male deaths is greater than 0.5.

Since a greater number of males are engaged in outdoor activities like construction and fishing, there is a comparatively large number of male deaths due to lightning strikes.