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Finding Critical Values of \({\chi ^2}\) For large numbers of degrees of freedom, we can approximate critical values of \({\chi ^2}\) as follows:

\({\chi ^2} = \frac{1}{2}{\left( {z + \sqrt {2k - 1} } \right)^2}\)

Here k is the number of degrees of freedom and z is the critical value(s) found from technology or Table A-2. In Exercise 12 鈥淪poken Words鈥 we have df = 55, so Table A-4 does not list an exact critical value. If we want to approximate a critical value of \({\chi ^2}\) in the right-tailed hypothesis test with \(\alpha \)= 0.01 and a sample size of 56, we let k = 55 with z = 2.33 (or the more accurate value of z = 2.326348 found from technology). Use this approximation to estimate the critical value of \({\chi ^2}\) for Exercise 12. How close is it to the critical value of \({\chi ^2}\)= 82.292 obtained by using Statdisk and Minitab?

Short Answer

Expert verified

The estimated critical value is equal to 81.54. The value obtained is quite close to the value obtained using technology (82.292).

Step by step solution

01

Given information

A sample of the number of words spoken in a day is considered.

The sample size is equal to 56. The value of the degrees of freedom is equal to 55.

The value of the z-score is equal to 2.33. The actual critical value of \({\chi ^2}\) is equal to 82.292.

02

Compute the approximate critical value

The approximate critical value has the following formula:

\({\chi ^2} = \frac{1}{2}{\left( {z + \sqrt {2k - 1} } \right)^2}\).

The values are given as follows.

  • k is equal to 55.
  • The z-score is equal to 2.33.

Substitute the above values in the formula to obtain the critical value, as shown.
\(\begin{array}{c}{\chi ^2} = \frac{1}{2}{\left( {2.33 + \sqrt {2\left( {55} \right) - 1} } \right)^2}\\ \approx 81.54\end{array}\).

Thus, the critical value is equal to 81.54.

03

Comparison

The critical value of\({\chi ^2}\)obtained using the formula (81.54) isquite close to the critical value of \({\chi ^2}\) obtained using technology (82.292).

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Most popular questions from this chapter

Calculating Power Consider a hypothesis test of the claim that the Ericsson method of gender selection is effective in increasing the likelihood of having a baby girl, so that the claim is p>0.5. Assume that a significance level of = 0.05 is used, and the sample is a simple random sample of size n = 64.

a. Assuming that the true population proportion is 0.65, find the power of the test, which is the probability of rejecting the null hypothesis when it is false. (Hint: With a 0.05 significance level, the critical value is z = 1.645, so any test statistic in the right tail of the accompanying top graph is in the rejection region where the claim is supported. Find the sample proportion in the top graph, and use it to find the power shown in the bottom graph.)

b. Explain why the green-shaded region of the bottom graph represents the power of the test.

In Exercises 9鈥12, refer to the exercise identified. Make subjective estimates to decide whether results are significantly low or significantly high, then state a conclusion about the original claim. For example, if the claim is that a coin favours heads and sample results consist of 11 heads in 20 flips, conclude that there is not sufficient evidence to support the claim that the coin favours heads (because it is easy to get 11 heads in 20 flips by chance with a fair coin).

Exercise 5 鈥淥nline Data鈥

Type I and Type II Errors. In Exercises 29鈥32, provide statements that identify the type I error and the type II error that correspond to the given claim. (Although conclusions are usually expressed in verbal form, the answers here can be expressed with statements that include symbolic expressions such as p = 0.1.).

The proportion of people who require no vision correction is less than 0.25.

In Exercises 9鈥12, refer to the exercise identified. Make subjective estimates to decide whether results are significantly low or significantly high, then state a conclusion about the original claim. For example, if the claim is that a coin favours heads and sample results consist of 11 heads in 20 flips, conclude that there is not sufficient evidence to support the claim that the coin favours heads (because it is easy to get 11 heads in 20 flips by chance with a fair coin).

Exercise 6 鈥淐ell Phone鈥

Finding Critical t Values When finding critical values, we often need significance levels other than those available in Table A-3. Some computer programs approximate critical t values by calculating t=dfeA2/df-1where df = n-1, e = 2.718, A=z8df+3/8df+1, and z is the critical z score. Use this approximation to find the critical t score for Exercise 12 鈥淭ornadoes,鈥 using a significance level of 0.05. Compare the results to the critical t score of 1.648 found from technology. Does this approximation appear to work reasonably well?

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