91影视

given,

The results of the study by P. Mackowiak et al. appeared in the article "A Critical Appraisal of $98.6掳F$ , the Upper Limit of the Normal Body Temperature, and Other Legacies of Carl Reinhold August Wunderlich"

MINITAB procedure:
Step 1: Choose Graph > Probability Plot.
Step 2: Choose Single, and then click OK.
Step 3: In Graph variables, enter the column of TEMP.
Step 4: Click OK.

Observation:

From the probability plot of the period, the observations are closer to a straight line. Therefore, the distribution of temperature is approximately normally distributed.

MINITAB procedure:

Step 1: Choose Graph 鈮� Boxplot or stat > EDA > Boxplot.

Step 2: Under Multiple Yrs, choose Simple. Click OK.

Step 3: in Graph variables, enter the data of TEMP.

Step 4: Click OK.

From the boxplot, it is clear that the distribution of temperature is approximately normally distributed.

MINITAB procedure:

Step 1: Choose Oraph > Histogram.

Step 2: Choose Simple, and then click OK.

Step 3: In Graph variables, enter the corresponding column of TEMP.

Step 4: Click OK.

From the histogram, It is clear that the space of the distribution is well-shaped.

MINITAB procedure:

Step 1: Select Graph > Stem and leaf.

Step 2: Select the column of variables in Graph variables.

Step 3: Select OK.

Stem-and-Leaf Display: TEMP

From the stem-and-leaf diagram, it is clear that the shape of the distribution is bell-shaped.

Yes, it is reasonable apples the one-mean z-test to the data because the distribution of temperature is approximately symmetric. That is, the shape of the distribution is bell-shaped.

State the null and alternative hypotheses:

Null hypothesis:

$H_0:渭={98.6}^{鈭�}\mathrm{F}$

That is, the mean body temperature of healthy humans does not differ from $98.6掳F$.

Alternative hypothesis:

$H_0:渭鈮�{98.6}^{鈭�}\mathrm{F}$

That is, the mean body temperature of healthy humans differs from $98.6掳F$.

Here, the significance level is, 伪=0.01.

MIN.TAB procedure:

Slep 1: Choose Stat > Basic Statistics > 1-Sample Z.

Step 2: in Samples in the Column, enter the column of Temperature.

Step 3- In Standard deviation, enter 0.63.

Step 4: In-Perform hypothesis test, enter the least mean as 98.6.

Step 5: Check Options, and enter your Confidence level as 99.

Step 6: Choose not equal in alternative.

Step 7: Click OK in all dialogue boxes.

One-Sample Z: TEMP

From the MINITAB output, the value of the test statistic is -7.29 and the P-value is 0 .

Rejection rule:

If P鈮の�, then reject the null hypothesis.

Here, the P-value is 0 which is less than the level of significance. That is, P(=0)鈮の�(=0.01).

Therefore, the null hypothesis is rejected at the 1% level.

Thus, it can be concluded that the test results are statistically significant at a 1% level of significance.

Interpretation:

The data provide sufficient evidence to conclude that the mean body temperature of healthy humans differs from $98.6掳F$ at a 1% level.