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We have been provided a sample mean, sample size, and population standard deviation. In the given case, use the one-mean z-test to perform the required hypothesis test at the 5%significance level.

x=20,n=32,=4,H0:=22,Ha:<22

Short Answer

Expert verified

The value ofzis-2.83, critical value is-1.645,P=0.002and rejectH0.

Step by step solution

01

Step 1. Given information.

Consider the given question,

x=20,n=32,=4,H0:=22,Ha:<22

02

Step 2. Consider the test hypothesis.

Consider the given hypothesis,

is the population mean.

The test hypothesis,

Ho:=22vs

Ha:<22

Therefore, the test is left tailed test.

And the level of significance is =0.05.

03

Step 3. Use the test statistics.

We want to find the hypothesis test about the mean ,

z=x-0n=20-22432=-2.83

Therefore, this is left tailed test with =0.05, the critical value is given below,

-za=-z0.05=-1.645

The rejection region is z<-z0.05.

Here, z=-2.83<-z0.05=-1.645

Hence, we reject Hoat 5% level of significances the value of the test statistic z falls in the rejection region.

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